?10 and ?8 = 101/4 and 81/3
Since, LCM of 4 and 3 is 12.
? 101/4 = 103/12 = (103)1/12 = (1000)1/12 = 12?1000
and 81/3 = 84/12 = (84)1/12 (4096)1/2 = 12?4096
? 4096 > 1000
Hence, 81/3 >101/4
? ?8 > ?10
Let the number be x.
According to the question,
x2 + (14)3 = 4425
? x2 = 4425 - (14)3
? x2 = 4425 - 2744
? x2 = 1681
? x = ?1681 = 41
?81 and ?1 = 811/2 and 11/2
Since, 1 < 81
? ?1 < ?81
?8 and ?1000 = 81/3 and 10001/3
Since 1000 > 8
? ?1000 > ?8
(x + 1)/(x - 1) - (x - 1)/(x + 1) = {(x + 1)2 - (x - 1)2} / {(x - 1) (x + 1)}
= (x2 + 1 + 2x) - (x2 + 1 - 2x) / (x2 - 1)
= 4x / (x2 - 1) = 4(?3 + ?2) / {(?3 + ?2)2 - 1}
= 4(?3 + ?2) / (3 + 2 + 2?6 - 1) = 4(?3 + ?2) / (4 + 2 ?6)
= 4(?3 + ?2) / 2 ?2 (?3 + ?2)
= ?2
Given that,
?16 + ?9.5 x 0.0085 x 18.9/0.021 x 0.0017 x 1.9
remove the decimal and simply the euqation.
= ?16 + ?95 x 85 x 18900/21 x 17 x 19
= 4 + ?5 x 5 x 900
= 4 + 5 x 30
= 4 + 150
= 154
74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
= (2 x 2) x (3 x 3) x (7 x 7) x ( 2 x 3 x 7)
? Least number which should be multiplied to 74088 to make it a perfect suqare = 2 x 3 x 7 = 42
Let the number be x.
Then, accordingto the question,
x2 = (75.15)2 - (60.12)2
? x2 = 5647.52 - 3614.41
? x2 = 2033.11
? x = 45.09
Let the total number of soliders in front be x. Then, total number of soliders in form of solid square = x2
According to the question, x2 + 31 = 16160
? x2 = 16129 ? x = ?16129
? x = 127
Let the total number of subbscribers be x.
Then, x2 = 2582449
? x = ?2582449 = 1607
Total collected amount = Rs. 29791
? Total number of student = ?29791 = 31
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