The square of an odd number cannot have 4 as the unit digit. The square of a 3 digit number will have at least 5 digit and at the most 6 digits. So. answer (A) is correct.
7/(3 + ?2) = [7 x (3- ?2)] / [(3 + ?2) x (3- ?2)]
= [7 x ( (3- ?2)] / 7
= 3- ?2
= 3 - 1.4142
= 1.5858
Let given expression = x
Then, ?12 + x = x
? 12 + x = x2
? x2 - x - 12 = 0
? (x - 4) (x + 3) = 0
So, x = 4 (neglecting x = -3)
?1 + 27/169 = (1 + N/13)
? ?196/169 = (1 + N/13)
? 14/13 = (1 + N/13)
? N/13 = (14/13 - 1 ) = 1/13
? N = 1
Given expression = ?(121 x 9) / (11 x 11)
= ?9
= 3
?2n = 64
? 2n/2 = 26
? n/2 = 6
? n = 12
?0.04 x 0.4 x a = 0.4 x 0.04 x ?b
? ?0.016 a = 0.016 x ?b
? ?a / ?b = 0.016/?0.016 = ?0.016
? ?a/b = ?0.016
So a/b = 0.016
L. C. M of 3, 4, 5, 6, 8 is 120
Now, 120 = 2 x 2 x 2 x 3 x 5
? Required number = (2 x 2 x 2 x 3 x 5) x (2 x 3 x 5)
= 3600
(?5 - ?3)/ (?5 + ?3)
= (?5 - ?3) / (?5 + ?3)
= (?5 - ?3)2 / (5 - 3)
= (5 + 3 - 2?5 x 3) / 2
= 2 (4 - ?15) / 2
= (4 - ?15)
a = [(?5 + 1) / (?5-1)] x [(?5 + 1) / (?5 + 1)]
= (?5 + 1)2 / (5 - 1)
= (5 + 1 + 2 ?5) / 4
= (3 + ?5) / 2
b = [(?5 - 1) / (?5 + 1)] x [(?5 - 1 ) / (?5 -1)]
= (?5 - 1 )2 / (5 - 1)
= (5 + 1 - 2?5) / 4
= (3 - ?5) / 2
Now a2 + b2 = [(3 + ?5)2 + (3 - ?5)2] / 4
= [2 x (9 + 5 )] / 4
= 7
ab = 1
? (a2 + ab + b2) / (a2 - ab + b2)
= (7 + 1) / (7 - 1)
= 8/6
= 4 / 3
216 = 2 x 2 x 2 x 3 x 3 x 3
= (2 x 2) x 2 x ( 3 x 3) x 3
Clearly, in order to make it a perfect square, it must be divided by 2 x 3 i.e., 6 .
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