?.04 = ?4/100
= 2/10
= 0.2
?4096 + ?40.96 + ?.004096
= ?4096 + ?4096/100 + ?4096/1000000
=?4096 + ?4096/10 + ?4096/1000
= 64 + 64/10 + 64/1000
= 70.464
Given Expression 112/?196 x ?579/12 x ?256/8
=(112/14) x (24/12) x (16/8)
= 32
?y/169= 54/39
? y/169 = (54/39) x (54/39)
? y= (54/39) x (54/39) x 169 = 324
In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
Total number of students = 480
percentage of total students passed = 75% of total student
= (75 x 480)/100 = 360 students
Now, using the condition from the question.
Let the number of boys be N
Then, 70% of N + 85% of (480 - N) = 360
? [(70 x N)/100] + [85 x (480 - N)]/100 = 360
? 70N - 85N + 40800 = 36000
? 40800 - 36000 = 85N - 70N
? 4800 = 15N
? N = 4800/15 = 320
? There are 320 boys who appeared for the examination,
?288 / ?128 = ?9/4
= 3/2
?10 x ?15
= ?10 x 15
= ?150
= ?25 x 6
= ?25 x ?6
= 5?6
Let √x / 200 = 0.02
Then, √x = 200 x 0.02 = 4.
So, x = 16
Let 250 / √x = 10.
Then √x= 250 / 10 = 25
∴ x = 625
√4375 / √7 = √4375 / 7
= √625
= 25
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