In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
Total number of students = 480
percentage of total students passed = 75% of total student
= (75 x 480)/100 = 360 students
Now, using the condition from the question.
Let the number of boys be N
Then, 70% of N + 85% of (480 - N) = 360
? [(70 x N)/100] + [85 x (480 - N)]/100 = 360
? 70N - 85N + 40800 = 36000
? 40800 - 36000 = 85N - 70N
? 4800 = 15N
? N = 4800/15 = 320
? There are 320 boys who appeared for the examination,
Let us assume that Arun uses N units of petrol everyday. so the amount of of petrol in the tank when it is full will be 10N. If he starts using 25% more petrol everyday. then the units of petrol he now use everyday will be
N(1 + 25/100) = 1.25N
So, the number of days his petrol will now last will be equal to (amount of petrol in tank) / (number of units used everyday)
= (10N) / (1.25N) = 10 / 1.25
= 8 days
In 1998
Let number of students in x = 3k
Number of students in y = 5k and
Number of students in z = 6k
Next year,
number of students in x = 3k + 20% of 3k = 18k/5
Number of students in y = 5k + 10% of 5k = 11k/2
Number of students in z = 6k + 20% of 6k = 36k/5
According to the question,
(18k/5) / (36k/5) = 1/2
Thus, data is insufficient.
Let expenses on wheat be 12N.
Expenses on meat = 17N.
Expenses on vegetables = 3N.
? Total expenses = 32N.
Increased expenses = ? (120% of 12N) + (130% of 17N) + (150% of 3N)]
= ? [(120/100) x 12N] + [(130/100) x 17N] + [(150/100) x 3N]
= ? [72N/5 + 221N/10 + 9N/2]
= ? (144N + 221N + 45N)/10
= ? 410N/10
= ? 41
? Total increase percentage = (9N/32N) x 100 %
= 225/8 %
= 281/8%
Let price of ghee before increment = ? N
Consumption = 10 kg
Then, expenditure on ghee = ? 10N
After increment,
Expenditure on ghee = 110% of 10N = 11N
Price of ghee = 132% of N = (N x 132)/100 = 33N/25 per kg
? Now consumption = (11N x 25) / 33N kg
= 81/3 kg
?y/169= 54/39
? y/169 = (54/39) x (54/39)
? y= (54/39) x (54/39) x 169 = 324
Given Expression 112/?196 x ?579/12 x ?256/8
=(112/14) x (24/12) x (16/8)
= 32
?4096 + ?40.96 + ?.004096
= ?4096 + ?4096/100 + ?4096/1000000
=?4096 + ?4096/10 + ?4096/1000
= 64 + 64/10 + 64/1000
= 70.464
?.04 = ?4/100
= 2/10
= 0.2
?288 / ?128 = ?9/4
= 3/2
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