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- Question
- Ram sells his goods 25% cheaper then Shyam and 25% dearer than Hari. How much percentage is Hari's goods cheaper than Shyam?
Options- A. 25
- B. 331/3
- C. 40
- D. 50
- Correct Answer
- 40
ExplanationLet the selling price of goods by shyam be = ? 100
? Selling price of goods by Ram = ? 75
Now, according to the question.
125% of selling price of goods by Hari = 75
? Selling price of goods by Hari = (100/125) x 75 = ? 60
So, Hari's goods are cheaper than shyam's good by
(40/100) x 100% = 40% - 1. In a test, Rajesh got 112 marks which was 32 more than the passing marks. Sonal got 75% marks which was 70 more than the passing marks. What is the minimum passing percentage of the test.?
Options- A. 35%
- B. 45%
- C. 40%
- D. 48% Discuss
- 2. An alloy of gold and silver weights 50g. It contains 80% gold. How much gold should be added to the alloy, so that percentage of gold is increased to 90?
Options- A. 50g
- B. 60g
- C. 30g
- D. 40g Discuss
- 3. A students was awarded certain marks in an examination. However, after re-evaluation, his marks were reduced by 40% of the marks that were originally awards to him, so that the new score now became 96. How many marks did the student lose after re-evaluation?
Options- A. 58
- B. 68
- C. 63
- D. 56 Discuss
- 4. A jogger desires to run a certain course in 1/4 less time than he usually takes. By What per cent must be increase his average running speed to accopplish the goal?
Options- A. 50%
- B. 20%
- C. 25%
- D. 331/3 Discuss
- 5. Sahil got 45 marks in Hindi, 47 marks in Science, 49 marks in Mathematics, 45 marks in Social Science and 32 marks in English. The Maximum marks of each subject is 50. How much overall percentage of marks did he get?
Options- A. 75%
- B. 56.4%
- C. 78%
- D. 87.2% Discuss
- 6. The ratio of the number of boys and girls in a school is 3 : 2. If 20% of the boys and 25% of the girls are scholarship holders, then the percentage of the students who do not get the scholarship, is?
Options- A. 78%
- B. 75 %
- C. 60%
- D. 55% Discuss
- 7. The price of ghee is increased by 32%. Therefore, a family reduces its consumption, so that the increment in price of ghee is only 10%. If consumption of ghee is 10 kg before the increment, then What is the consumption now?
Options- A. 81/3 kg
- B. 83/4 kg
- C. 81/2 kg
- D. 9 kg Discuss
- 8. The expenses on wheat, meat and vegetable of a family are in the ratio 12 : 17 : 3. The prices of these articles are increased by 20%, 30% and 50% respectively, The total expenses of the family on these articles are increased by?
Options- A. 231/3%
- B. 281/8%
- C. 271/8%
- D. 251/7% Discuss
- 9. In 1998, ratio of the numbers of students taking examinations in x and z states are respectively 3 : 5 : 6. Next year, the numbers of students are increased by 20%, 10% and 20% respectively. If ratio of the numbers of students in states x and z is 1 : 2, then find the number of students who sit to take examination in 1998.?
Options- A. 5000
- B. 6000
- C. 75000
- D. Data is insuffcient Discuss
- 10. The tank-full of petrol in Arun's motor-cycle lasts for 10 days. If he starts using 25% more everyday, how many days will the tank-full of petrol last?
Options- A. 5
- B. 6
- C. 7
- D. 8 Discuss
Percentage problems
Search Results
Correct Answer: 40%
Explanation:
Let maximum marks be N .
According to the question,
75N/100 - 70 = 112 - 32
? 75N/100 = 80 + 70
? 75N/100 = 150
? N = 200
Passing marks = 112 - 32 = 80
(as Rajesh got 112 marks which is 32 more than the passing marks)
? Minimum passing marks percentage
= (80/200) x 100%
= 40%
Correct Answer: 50g
Explanation:
Gold in 50g of alloy = (80 x 50)/100 = 40 g
Let W gram gold must be added.
Now, according to the question,
(40 + W) / (50 + W) = 90/100
? 100( 40 + W) = 90 (50 + W)
? 10(40 + W) = 9 (50 + W)
? 400 + 10W = 450 + 9W
? W = 450 - 400
? W = 50g
Thus, 50 g of gold must be added to make it 90%
Correct Answer:
Explanation:
Let a student was awarded in exam = N marks
According to the question,
After re-evaluation his score
? N - N x (40/100) = 96
? N - 2N/5 = 96
? 5N - 2N/5 = 96
? 3N/5 = 96
? N = (5 x 96)/3 = 5 x 32
? N = 160
So, a student was awarded by 160 marks in examination
? Reduced marks after re-evaluation = 160 - 96 = 64
Correct Answer: 331/3
Explanation:
Let usual speed and usual time taken by the jogger are D and T, respectively.
Let his new speed be D'. Then,
DT = (3D'/4)T
? D = 3D'/4
? D' = 4D/3
Thus, he has to increased his speed by
[(4D/3 - D) / D] x 100% .
= 331/3 %
Correct Answer: 87.2%
Explanation:
Total marks obtained = [45 + 47 + 49 + 45 + 32] = 218
Maximum marks = 5 x 50 = 250
? overall percentage = (218/250) x 100% = 87.2%
Correct Answer: 78%
Explanation:
Let number of boys be 300.
Number of girls = 200
Boys holding scholarship = (20/100) x 300 = 60
Girls holding scholarship = (25/100) x 200 = 50
Total student holding scholarship = 60 + 50 = 110
? Percentage of students not holding scholarship = [(500 -110) / 500] x 100%
= (390/500) x 100 %
= 78%
Correct Answer: 81/3 kg
Explanation:
Let price of ghee before increment = ? N
Consumption = 10 kg
Then, expenditure on ghee = ? 10N
After increment,
Expenditure on ghee = 110% of 10N = 11N
Price of ghee = 132% of N = (N x 132)/100 = 33N/25 per kg
? Now consumption = (11N x 25) / 33N kg
= 81/3 kg
Correct Answer: 281/8%
Explanation:
Let expenses on wheat be 12N.
Expenses on meat = 17N.
Expenses on vegetables = 3N.
? Total expenses = 32N.
Increased expenses = ? (120% of 12N) + (130% of 17N) + (150% of 3N)]
= ? [(120/100) x 12N] + [(130/100) x 17N] + [(150/100) x 3N]
= ? [72N/5 + 221N/10 + 9N/2]
= ? (144N + 221N + 45N)/10
= ? 410N/10
= ? 41
? Total increase percentage = (9N/32N) x 100 %
= 225/8 %
= 281/8%
Correct Answer: Data is insuffcient
Explanation:
In 1998
Let number of students in x = 3k
Number of students in y = 5k and
Number of students in z = 6k
Next year,
number of students in x = 3k + 20% of 3k = 18k/5
Number of students in y = 5k + 10% of 5k = 11k/2
Number of students in z = 6k + 20% of 6k = 36k/5
According to the question,
(18k/5) / (36k/5) = 1/2
Thus, data is insufficient.
Correct Answer: 8
Explanation:
Let us assume that Arun uses N units of petrol everyday. so the amount of of petrol in the tank when it is full will be 10N. If he starts using 25% more petrol everyday. then the units of petrol he now use everyday will be
N(1 + 25/100) = 1.25N
So, the number of days his petrol will now last will be equal to (amount of petrol in tank) / (number of units used everyday)
= (10N) / (1.25N) = 10 / 1.25
= 8 days
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