Let the total number of children be N.
Then, N x (20/100) x N = 720
? N2/5 = 720
? N2 = 5 x 720 = 5 x 5 x 144
? N = ?5 x 5 x 144 = 60
Number of sweets received by each child = (20/100) x 60 = 12
Let total number of employee be 100.
? Number of men = 60% of 100 = 60
and number of women = 40% of 100 = 40
Number of men drawing more than ? 50000 = 40% of 60 = 24 men
Since, number of total employees drawing more than ? 50000 = 36% of 100 = 36
Number of women who more than ? 50000 = 36 - 24 = 12
Number of women who draw less than ? 50000 = 40 - 12 = 28
Percentage of women who draw less then ? 50000 per year = (28 x 100)/40 = 70%
Suppose N% familes own both a car and a phone, then
percentage of the families owing only a phone = 25 - N
Percentage of the families owing only a car = 15 - N
? (25 - N) +(15 - N) + N + 65 = 100
? N = 5
Percentage of families who have either a car or a phone = (25 - 5) + (15 - 5) + 5 = 35
So, Statement ll is correct.
Now, suppose the total number of families in the town be A.
? (5 x A)/100 = 2000 ? A = 40000
So, Statement lll is also correct.
40% = 24 questions.
? Total question = (100/40) x 24 = 60
Clearly, it is given that 40% failed in Hindi, so those who passed in Hindi = (100 - 40)% = 60%
Let the number of boys = x
then x + 7x/10 = 85
? x = 50
? No. of girls = 85 - 50 = 35
(i) Number of boys playing only badminton =50% of boys
= 50/100 x 50 = 25
(ii) Number of children playing only table tennis
= 40% of total no. of children
= 40/100 x 85 = 34
(iii) Total no. of children playing both badminton and table tennis = 12
Hence, number of girls playing only badminton = 85 - (25 + 34 + 12)
= 85 - 71 = 14.
Let quantity of alcohal = 1000 L
Quantity of alcohal after 1st process = 80% of 1000 L = 800 L
Quantity of alcohol after 2nd process = 80% of 800 L = 640 L
Quantity of alcohol after 3rd process = 80% of 640 L = 512 L
? Required percentage = (512/1000) x 100 = 51.2%
Here, a = 20%
Required percentage loss = [a / (100 + a)] x 100%
= [20/(100 + 20)] x 100%
= (20/120) x 100%
= 162/3%
Require number = 1240 x (25/100)
= 310
Let the number be N.
According to the question,
(78 - 59)% of N = 323
? (19 x N)/100 = 323
? N = (323 x 100)/19 = 1700
? 62% of 1700 = (62/100) x 1700 = 1054
Increase in percentage of longer pipe compared to shorter pipe
= [(70 - 30)/30] x 100%
= (40/30) x 100%
= 400/3 %
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