A student attempted 24 question and secured full marks in all of them. If he obtained 40% in the test and each question carried equal marks, then what was the total number of questions in the test?

Clearly, it is given that 40% failed in Hindi, so those who passed in Hindi = (100 - 40)% = 60%

Let the number of boys = x
then x + 7x/10 = 85
? x = 50
? No. of girls = 85 - 50 = 35
(i) Number of boys playing only badminton =50% of boys
= 50/100 x 50 = 25
(ii) Number of children playing only table tennis
= 40% of total no. of children
= 40/100 x 85 = 34
(iii) Total no. of children playing both badminton and table tennis = 12
Hence, number of girls playing only badminton = 85 - (25 + 34 + 12)
= 85 - 71 = 14.

Reduction in consumption = { m / (100 + m)} x 100%
= (25/125) x 100%
= 20%

Suppose that his salary = Rs. 100

House Rent = Rs.10
so, Balance = Rs. 90

Expenditure on education = Rs. (15 x 90) / 100= Rs.13.50
Balance =Rs.76.50

Expenditure on clothes = Rs.(10 x 76.50) / 100 = Rs. 7.65
Balance now = Rs.68.85

If balance is Rs. 68.85, salary =Rs. 100
If balance is Rs. 1377, salary = Rs.(100/68.85) x 1377 = Rs. 2000

? 36% of N = (113 + 85)
? N = (100 x 198) / 36 = 550

Suppose N% familes own both a car and a phone, then
percentage of the families owing only a phone = 25 - N
Percentage of the families owing only a car = 15 - N
? (25 - N) +(15 - N) + N + 65 = 100
? N = 5
Percentage of families who have either a car or a phone = (25 - 5) + (15 - 5) + 5 = 35
So, Statement ll is correct.

Now, suppose the total number of families in the town be A.
? (5 x A)/100 = 2000 ? A = 40000
So, Statement lll is also correct.

Let total number of employee be 100.
? Number of men = 60% of 100 = 60
and number of women = 40% of 100 = 40
Number of men drawing more than ? 50000 = 40% of 60 = 24 men
Since, number of total employees drawing more than ? 50000 = 36% of 100 = 36
Number of women who more than ? 50000 = 36 - 24 = 12
Number of women who draw less than ? 50000 = 40 - 12 = 28
Percentage of women who draw less then ? 50000 per year = (28 x 100)/40 = 70%

Let the total number of children be N.
Then, N x (20/100) x N = 720
? N²/5 = 720
? N² = 5 x 720 = 5 x 5 x 144
? N = ?5 x 5 x 144 = 60
Number of sweets received by each child = (20/100) x 60 = 12

Let quantity of alcohal = 1000 L
Quantity of alcohal after 1st process = 80% of 1000 L = 800 L
Quantity of alcohol after 2nd process = 80% of 800 L = 640 L
Quantity of alcohol after 3rd process = 80% of 640 L = 512 L
? Required percentage = (512/1000) x 100 = 51.2%

Here, a = 20%
Required percentage loss = [a / (100 + a)] x 100%
= [20/(100 + 20)] x 100%
= (20/120) x 100%
= 16²/₃%