Let the Hari Lal was having R rupees in beginning.
? R - [40% of R + 25% of R + 15% of R + 5% of R] = 1305
? R - 85% of R = 1305
? 15% of R = 1305
? R = (1305 x 100)/15 = 8700
Let the number of students appearing for examination in the year 1998 in the states A, B and C be 3N, 5N,and 6N respectively.
According to the question, {(3N x 120)/100} / {(6N x 110)/100} = 1/2
Its true for every N so, The data is inadequate.
Number of females = 156800 x 100/80 = 196000
? Number of males = 7/8 x 196000 = 171500
Total population = 196000 + 171500 = 367500
Number of student who speak only English =30% of 60 = 18
Number of student who speak Hindi and English =20% of 60 =12
?Number of student who speak only Hindi = (60 - 30) = 30
?Number of student who speak Hindi = 30 + 12 = 42
Suppose there are 8y questions were asked apart from the 41 question.Then
37 + 5y/41 + 8y = 80% = 4/5
? 185 + 25y = 164 + 32y
? 7y = 21
? y = 3
? Total no. of questions = 41 + 8 x 3 = 65.
? J = 40% of A =2A/5
? P = 1/4 x 2A/5 = A/10
? A/10 - 200 = 600
? A/10 = 800
? A = Rs. 8000
? 30% of 180 + N% of 150 = 50% of (180 + 150)
? 54 + (N x 150)/100 = 165
? 3N/2 = 111
? N = (111 x 2) / 3 =74
? 36% of N = (113 + 85)
? N = (100 x 198) / 36 = 550
Suppose that his salary = Rs. 100
House Rent = Rs.10
so, Balance = Rs. 90
Expenditure on education = Rs. (15 x 90) / 100= Rs.13.50
Balance =Rs.76.50
Expenditure on clothes = Rs.(10 x 76.50) / 100 = Rs. 7.65
Balance now = Rs.68.85
If balance is Rs. 68.85, salary =Rs. 100
If balance is Rs. 1377, salary = Rs.(100/68.85) x 1377 = Rs. 2000
Reduction in consumption = { m / (100 + m)} x 100%
= (25/125) x 100%
= 20%
Let the number of boys = x
then x + 7x/10 = 85
? x = 50
? No. of girls = 85 - 50 = 35
(i) Number of boys playing only badminton =50% of boys
= 50/100 x 50 = 25
(ii) Number of children playing only table tennis
= 40% of total no. of children
= 40/100 x 85 = 34
(iii) Total no. of children playing both badminton and table tennis = 12
Hence, number of girls playing only badminton = 85 - (25 + 34 + 12)
= 85 - 71 = 14.
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