Here, R = 20%, A = 3.5 kg and P = ? 770
According to the formula ,
Actual price of rice = [PR /(100 - R)] A
= [(20 x 770) / (100 - 20)] x 3.5
= [(20 x 770) / (80 x 3.5)
= ? 55
Let the total number of staff be 100.
? Female staff = 40
Male staff = (100 - 40) = 60
Votes cast by females = (40/100) x 40 = 16
Votes cast by males = (60/100) x 60 = 36
Votes cast by both (males + females) = 16 + 36 = 52
? Percentage votes obtained = 52%
Let the maximum aggregate marks be N
According to the question,
10% of N = 296 - 222
? N/10 = 74
? N = (74 x 10) = 740
Mr. Sen's monthly income
= (Bina + Anita)'s monthly income = 775200/12 = ? 64600
According to the question.
Bina's monthly income = 90% of Anita's monthly income
? Bina/Anita = 90/100 = 9 /10
? Bina : Anita = 9 : 10
? Bina's Monthly salary
= (9/19) x 64600
= ? 30600
According to the formula .
Percentage of students passed in both the subjects
= [100 - (x + y - z)]%
= [100 - (49 + 36 - 15)]% = 30%
Let total number of students = N
According to the question,
(N x 30)/100 = 450
? N = (450/30) x 100 = 1500
? Total number of students = 1500
Quantity of alcohol in 5 L of solution = (40/100) x 5 = 2 L
Quantity of alcohol in 6 L of solution = 2 L
? Strength of alcohol in new solution = (2/6) x 100%
= 331/3%
Let original price be ? 100 per kg.
Money required to buy 50 kg of rice = ? (100 x 50) = ? 5000
New price = (100 - 5) = ? 95 per kg
? Quantity of rice bought = (5000/95) kg = 52.63 kg
Increase in the price of rice = 25%
? increased in ? 400 = 25% of ? 400
= 400 x (25/100) = ? 100
? Increased in rate of rice in 25%, there are 20kg less rice in ? 400 i.e., rate of 20 kg rice
= ? 100
= Rate of 1kg rice = 100/20 = ? 5
? Increased price of rice = ? 5 per kg
Number of sweets received by every students = 15% of 40 = (40 x 15)/100 = 6
? Number of sweets received by 40 students = 40 x 6 = 240
Number of sweets received by each teacher = 20% of 40 = (40 x 20)/100 = 8
? Number of sweets received by 5 teachers = 8 x 5 = 40
? Total number of sweets = 240 + 40 = 280
Let the weight of fresh grapes be W.
Quantity of water in it = (80/100) x W = 4W/5
Quantity of pulp in it = W - (4W/5) = W/5
Quantity of water in 500 gm dry grapes
= (10/100) x 500 = 50 kg
? Quantity of pulp in it = (500 -50) = 450 kg
W/5 = 450
? W = 2250 kg
Let original rate of rice be ? x per kg
Reduced rate = ? [(100 - 6.25) x (1/100) x W]
= ? 15W/16 per kg
According to the question
120/(15W/16) - 120/W = 1
? (120 x 16)/15W - 120/W = 1
? 120 x 16 - 1800 = 15W
? 128 - 120 = W
? W = ? 8 per kg.
? Reduced rate = ? (15/16) x 8 per kg
=? 7.50 per kg
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