32% of 750 = 750 x (32/100) = 240
From option (a), 23% of 600
= 600 x 23/100 = 138
From option (b), 46 % of 207
= 207 x 46/100 = 95.22
From option (c), 98% of 250
= 250 x 98/100 = 245
From option (d), 75% of 320
= 320 x 75/100 = 240
Hence, from option (d), satisfies equality of the equation.
Let maximum marks of the exam is N.
According to the question,
Marks obtained by Vidaya = Marks obtained by Aryan + 296
? N x (76/100) = 350 + 296
? N x (76/100) = 646
? N = (646 x 100)/7
? N = 8.5 x 100 = 850
? N = 850
Last year number of boys in school = 610
? Number of boys in school this year = 610 - (610 x 20)/100
= 610 - 122 = 488
? Number of girls in school this year
= Number of boys in school this year x 175%
= (488 x 175)/100
= (488 x 7)/4
= 122 x 7
= 854
Hence, number of girls in school this year in 854.
Let the total number of votes = N
According to the question,
75% of 98% of 75% of N = 9261
[? 2% votes were rejected]
? (N x 75 x 98 x 75) / (100 x 100 x 100) = 9261
? N = (9261 x 100 x 100 x 100) / (75 x 75 x 98) = 16800
Let sale in 2008 = 100
Sale in 2009 = 20
Sale in 2010 = 100
? Required increases = [(100 - 20)/20] x100
= (80/20) x 100 = 400%
Let cost prices of two article be 3N and 4N respectively then
(110% of 3N) / (4N + 4) = 3/4
? 1.1N / (N + 1) = 1
? 1.1N = N + 1
? 0.1 N = 1
? N = 10
Thus, cost price of the second article is 4 x 10 = ? 40
For class X, let the students passed in first class = a%
Then, by condition given in question
a% of 30 = 24
? (a x 30) /100 = 24
? a = 80%
Now, for class Y let the student passed in first class = b%
Then, according to the question,
b% of 35 = 28
? (b x 35)/100 = 28
? b = (28 x 100)/35 = 80%
Hence, both classes have equal percentage of student getting first class.
Annual household expenses
= ? (25% of 4.32 x 105)
= ? (25/100) x 4.32 x 105
= ? ( 25 x 4.32 x 103)
? Household expenses for 8 months
= ? [(25 x 4.32)/(12 x 8)] x 103)
= ? 72000
Required salary in October
= 6300 x (104/100) x (104/100)
= 63 x 104 x 1.04
= ? 6814.08
? ? 6814
Quantity of alcohol in 5 L of solution = (40/100) x 5 = 2 L
Quantity of alcohol in 6 L of solution = 2 L
? Strength of alcohol in new solution = (2/6) x 100%
= 331/3%
According to the formula .
Percentage of students passed in both the subjects
= [100 - (x + y - z)]%
= [100 - (49 + 36 - 15)]% = 30%
Let total number of students = N
According to the question,
(N x 30)/100 = 450
? N = (450/30) x 100 = 1500
? Total number of students = 1500
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