Let sale in 2008 = 100
Sale in 2009 = 20
Sale in 2010 = 100
? Required increases = [(100 - 20)/20] x100
= (80/20) x 100 = 400%
Let cost prices of two article be 3N and 4N respectively then
(110% of 3N) / (4N + 4) = 3/4
? 1.1N / (N + 1) = 1
? 1.1N = N + 1
? 0.1 N = 1
? N = 10
Thus, cost price of the second article is 4 x 10 = ? 40
After removing 25% of blue balls,
Total blue balls left = 75% of 100
= (75/100) x 100 = 75
After removing 50% of red balls, total red balls left = 50% 0f 50 = (50 x 50) / 100 = 25
? Required percentage = [50/(75 + 25 + 50)] x 100
= (50/150) x 100
= 331/3 %
Net effect on area = -20 + 10 + [(-20 )(10)/100] %
= (-10 - 2) % = -12%
Now, after this mistake new area = (100 - 12)% of 200
= (88/100) x 200
= 176 sq cm
Total marks scored by Mathew in all subjests = 42 + 51 + 58 + 35 + 48 = 234
? Maximum marks is 60 in any subject.
? Maximum marks = 60 x 5 = 300
? Percentage of Mathew's marks
= [(Marks obtained / Maximum marks)] x 100
= (234 / 300) x 100
= 234/3 = 78%
B's marks = C's marks + 5% of 400
= 300 + 20 = 320
Now , A's marks = B's marks + 10% of 400
= 320 + 40 = 360
Let the total number of votes = N
According to the question,
75% of 98% of 75% of N = 9261
[? 2% votes were rejected]
? (N x 75 x 98 x 75) / (100 x 100 x 100) = 9261
? N = (9261 x 100 x 100 x 100) / (75 x 75 x 98) = 16800
Last year number of boys in school = 610
? Number of boys in school this year = 610 - (610 x 20)/100
= 610 - 122 = 488
? Number of girls in school this year
= Number of boys in school this year x 175%
= (488 x 175)/100
= (488 x 7)/4
= 122 x 7
= 854
Hence, number of girls in school this year in 854.
Let maximum marks of the exam is N.
According to the question,
Marks obtained by Vidaya = Marks obtained by Aryan + 296
? N x (76/100) = 350 + 296
? N x (76/100) = 646
? N = (646 x 100)/7
? N = 8.5 x 100 = 850
? N = 850
32% of 750 = 750 x (32/100) = 240
From option (a), 23% of 600
= 600 x 23/100 = 138
From option (b), 46 % of 207
= 207 x 46/100 = 95.22
From option (c), 98% of 250
= 250 x 98/100 = 245
From option (d), 75% of 320
= 320 x 75/100 = 240
Hence, from option (d), satisfies equality of the equation.
For class X, let the students passed in first class = a%
Then, by condition given in question
a% of 30 = 24
? (a x 30) /100 = 24
? a = 80%
Now, for class Y let the student passed in first class = b%
Then, according to the question,
b% of 35 = 28
? (b x 35)/100 = 28
? b = (28 x 100)/35 = 80%
Hence, both classes have equal percentage of student getting first class.
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