Discussion
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- Question
- The prices of sugar is incerased by 25%. If a family wants to keep its expenses on sugar unaltered, then the family will have to reduce the consumption of sugar by
Options- A. 20%
- B. 21%
- C. 22%
- D. 25%
- Correct Answer
- 20%
ExplanationLet original price be ? 100
Then, increased price = ? 125
? Reduction in consumption
= [(125 - 100)/125 ] x 100%
= (25/125) x 100 %
= 20% - 1. Mangulal a shopkeeper, marks the prices of his goods at 20% higher than the original price. After that he allows a discount of 5%. What profit or loss did he get?
Options- A. 14% (profit)
- B. 14% (loss)
- C. 16% (loss)
- D. 16% (profit) Discuss
- 2. Because of scarcity of rainfall, the price of a land decrease by 12% and its production also decrease by 4%. What is the total effect on revenue?
Options- A. Loss of 16%
- B. Gain of 15%
- C. Loss of 15.48%
- D. Gain of 15.48% Discuss
- 3. In an examination, the marks obtained by Shantanu is 40% less than the marks obtained by Kamal, then marks obtained by Kamal is how much per cent more than the marks obtained by Shantanu?
Options- A. 552/3 %
- B. 443/5 %
- C. 331/3 %
- D. 662/3 % Discuss
- 4. 12 of 26% of 5/78 of 38% of 7/152 of 10000 =?
Options- A. 38
- B. 35
- C. 41
- D. 52 Discuss
- 5. A man losses 20% of his money. After sending 25 % of the remainder, he has ? 480 left. What is the amount of money he originally had?
Options- A. ? 600
- B. ? 720
- C. ? 800
- D. ? 840 Discuss
- 6. If the prices of tea falls down by 6% by how much per cent must a householder increased its consumption, so as not to decreased expenditure?
Options- A. 516/47%
- B. 418/67%
- C. 618/47%
- D. 617/47% Discuss
- 7. A student has to score 40% marks to get through. if he gets 40 marks and fails by 40 marks, then find the maximum marks set for the examination.?
Options- A. 200
- B. 250
- C. 300
- D. 150 Discuss
- 8. A candidate scores 20% and fails by 50 marks, while another candidate who score 40% marks, gests 30 marks more than the minimun required marks to pass the examination. Find the maximum marks for the examination.
Options- A. 500
- B. 450
- C. 300
- D. 400 Discuss
- 9. The population of a town is 126800. It increase by 15% in the 1st year and decrease by 20% in the 2nd year. What is the population of the town at the end of 2 yr.
Options- A. 174984
- B. 135996
- C. 116656
- D. 145820 Discuss
- 10. The population of a town is 705600. If it increases at the rate of 5% per annum, then what will be its population 2yr hence?
Options- A. 777924
- B. 777881
- C. 778781
- D. 797724 Discuss
Percentage problems
Search Results
Correct Answer: 14% (profit)
Explanation:
Given that, a = 20% and b = 5%
According to the formula
Required percentage = [20 - 5 - {20 x (5/100)}% = 14%
Correct Answer:
Explanation:
Net effect = [- 12 - 4 + {(-12) (-4)/100}]%
= (-16 + 0.48)%
= -15.52%
Correct Answer: 662/3 %
Explanation:
Let kamal's marks be 100
? Shantanu's marks = 60
Kamal has 40 marks more than Shantanu
? Required percentage = (40/60) x 100%
= 662/3 %
Correct Answer: 35
Explanation:
Ans = 12 x (26/100) x (5/78) x (38/100) x (7/152) x 10000
= 12 x (5/3) x (7/4)
= 35
Correct Answer: ? 800
Explanation:
Let a man have = ? N.
Remainder money, after losses 20% of his money
= N - 20% of N
= N - (N x 20)/100
= (5N - N)/5
= 4N/5
Remainder money, after spending 25% of his remainder money
= 4N/5 - 25% of (4N/5)
= 4N/5 - (4N/5) x (25/100)
= 4N/5 - N/5
= (4N - N)/5
= 3N/5
According to the question,
3N/5 = 480
? x = 480 x 5/3 = ? 800
Correct Answer: 618/47%
Explanation:
Let original price be ? 100
Then, reduced price = ? 94
? Increase in consumption
= [(100 - 94)/94] x 100 %
= (6/94) x 100 %
= 618/47%
Correct Answer: 200
Explanation:
Let maximum marks be N.
According to the question,
40N/100 = 40 + 40
? 40N/100 = 80
? N = 200
Correct Answer: 400
Explanation:
Let the maximum marks be N.
According to the question,
(20N/100) + 50 = (40N/100) - 30
? 20N/100 = 80
? N = (80 x 100)/20 = 400
Correct Answer: 116656
Explanation:
Given, R = 15% and R2 = 20%
Required population
= P(1 + R1/100) (1 - R2/100)
= 126800(1 + 15/100) (1- 20/100)
= 126800 (1 + 3/20 ) (1- 1/5)
= 126800 x (23/20) x (4/5) = 116656
Correct Answer: 777924
Explanation:
Given that,
P = 705600, R = 5% and n = 2
According to the formula,
Population after n yr = p(1 + R/100)n
? Population after 2 yr.
= 705600 x (1+ 5/100)2
= 705600 x (105/100)2
= 705600 x (21/20 x 21/20) = 777924
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