Mangulal a shopkeeper, marks the prices of his goods at 20% higher than the original price. After that he allows a discount of 5%. What profit or loss did he get?

Net effect = [- 12 - 4 + {(-12) (-4)/100}]%
= (-16 + 0.48)%
= -15.52%

Let kamal's marks be 100
? Shantanu's marks = 60
Kamal has 40 marks more than Shantanu
? Required percentage = (40/60) x 100%
= 66²/₃ %

Ans = 12 x (26/100) x (5/78) x (38/100) x (7/152) x 10000
= 12 x (5/3) x (7/4)
= 35

Let a man have = ? N.
Remainder money, after losses 20% of his money
= N - 20% of N
= N - (N x 20)/100
= (5N - N)/5
= 4N/5

Remainder money, after spending 25% of his remainder money
= 4N/5 - 25% of (4N/5)
= 4N/5 - (4N/5) x (25/100)
= 4N/5 - N/5
= (4N - N)/5
= 3N/5

According to the question,
3N/5 = 480
? x = 480 x 5/3 = ? 800

Given that, P = ? 15000, and Q = 8

According to the formula,
Required new price = [(100 - Q)/100] x P
= [(100 - 8)/100] x 15000
= (92/100) x 15000
= ? 13800

Let original price be ? 100
Then, increased price = ? 125

? Reduction in consumption
= [(125 - 100)/125 ] x 100%
= (25/125) x 100 %
= 20%

Let original price be ? 100
Then, reduced price = ? 94
? Increase in consumption
= [(100 - 94)/94] x 100 %
= (6/94) x 100 %
= 6¹⁸/₄₇%

Let maximum marks be N.

According to the question,
40N/100 = 40 + 40
? 40N/100 = 80
? N = 200

Let the maximum marks be N.

According to the question,
(20N/100) + 50 = (40N/100) - 30
? 20N/100 = 80
? N = (80 x 100)/20 = 400

Given, R = 15% and R₂ = 20%
Required population
= P(1 + R₁/100) (1 - R₂/100)
= 126800(1 + 15/100) (1- 20/100)
= 126800 (1 + 3/20 ) (1- 1/5)
= 126800 x (23/20) x (4/5) = 116656