A man spends 75% of his income. This income is increased by 20% and he increased his expenditure by 10%. His savings are increased by?

B's salary is less than A's by (30 x 100)/130 % = 23¹/₁₃%

P = 6q. Thus q is less than p by 5q
? q is less than p by = {(6q - q)/6q} x 100%
= ( 5q/6q) x 100 % = 83¹/_{3 %}

Let original wages = Rs. 100
Reduced wages = Rs. 50
Increased wages = 150% of Rs. 50 = (150 x 50)/100 = Rs. 75
? Loss = 25%

Increase in 3 years over 100 = 100 x {1 + 7/(2 x 100)}³
= (100 x 207/200 x 207/200 x 207/200)
= (200 + 7)³ / 80000
= 88869743 / 80000 = 110.8718

Required increase % = (110.8 - 100)% = 10.8%

Value of machine 2 years later = Rs. [ 4000 x {(1 - 10)/10)}²]
= Rs. (4000 x 9/10 x 9/10)
= Rs. 3240

Let original price = Rs. 100
Reduced price = Rs. 75
Increase on Rs. 75 = Rs. 25
Increase on Rs. 100 = (25 x 100)/75 % = 33¹/₃ %

Let the original fraction be p/q
Now, (120% of p) / (90% of q) = 16 / 21
? 4p / 3q = 16/21
? p / q = (16/21) x (3/4) = 4 / 7

? Milk = 90% 0f 40 = 36 litres and water = 4 litres.
Let L litre water to be added in order to make 20% water in new mixture.
? {(4 + L) / (40 + L)} x 100 = 20
? 20 x (40 + L) = 100 x (4 + L)
? 80 x L = 400
? L = 5 litres .

Suppose boys = 3N and girls = 2N
Not adults = (80% of 3N) + (75% of 2N) = (12N/5 + 3N/2) = 39N/10
? Required percentage = (39N/10 / 1/5N) x 100 % = 78%

Let the total number of students be 100
Then, n(A ? B) = n(A) + n(B) - n(A ? B) = (72 + 44 - 100)% = 16%
Now,16% of N = 40
? (16 x N) / 100 = 40
? N = (100 x 40) / 16 = 250