A man's wages were decreased by 50%. Again the reduced wages were increased by 50%. He has a loss of?

Increase in 3 years over 100 = 100 x {1 + 7/(2 x 100)}³
= (100 x 207/200 x 207/200 x 207/200)
= (200 + 7)³ / 80000
= 88869743 / 80000 = 110.8718

Required increase % = (110.8 - 100)% = 10.8%

Value of machine 2 years later = Rs. [ 4000 x {(1 - 10)/10)}²]
= Rs. (4000 x 9/10 x 9/10)
= Rs. 3240

? 540 = H(1 + 20/100)²
? H = (540 x 5/6 x 5/6) = 375 cm

Population after 2 years
=8000(1 + 10/100) (1 + 20/100)
= (8000 x 11/10 x 6/5) = 10560

Let price = Rs. 100, sale = 100
Then sale value = Rs. (100 x 100) = Rs. 10000
New sale value = Rs. (70 x 120) = Rs. 8400
Decrease% = (1600/10000) x 100 % = 16%

P = 6q. Thus q is less than p by 5q
? q is less than p by = {(6q - q)/6q} x 100%
= ( 5q/6q) x 100 % = 83¹/_{3 %}

B's salary is less than A's by (30 x 100)/130 % = 23¹/₁₃%

Let income = Rs. 100
Then expenditure = Rs. 75 and saving = Rs. 25
New expenditure = 110% of Rs. 75 = Rs. 165 / 2
New saving = Rs. (120 - 165/2) = Rs. 75/2
Increase in saving = Rs. (75/2 - 25) = Rs. 25/2
? Increase% = (25/2) x (1/25) x 100% = 50%

Let original price = Rs. 100
Reduced price = Rs. 75
Increase on Rs. 75 = Rs. 25
Increase on Rs. 100 = (25 x 100)/75 % = 33¹/₃ %

Let the original fraction be p/q
Now, (120% of p) / (90% of q) = 16 / 21
? 4p / 3q = 16/21
? p / q = (16/21) x (3/4) = 4 / 7