The population of a town is 8000. It increases by 10% during first year and by 20% during the second year. The population after 2 years will be?

Let price = Rs. 100, sale = 100
Then sale value = Rs. (100 x 100) = Rs. 10000
New sale value = Rs. (70 x 120) = Rs. 8400
Decrease% = (1600/10000) x 100 % = 16%

Alcohol in 15 litres =(20 x 15)/100 litres = 3 litres
Now, alcohol in 18 litres = 3 litres

? strength of alcohal =(3/18) x 100 % = 16²/₃%

Let tax = Rs. 100 and Consumption = 100 units
Original expenditure = Rs. (100 x 100) = 10000
New expenditure = Rs. (120 x 80) = Rs. 9600
? Decreased in expenditure = (400 x 100)/1000 % = 4%

Reduction in consumption = (20/120) x 100% = 50/3%
? Reduction in consumption /Original consumption = (50/3) / 100 = 1/6 = 1 : 6

? (62% of N - 38% of N) =144
? 24% of N = 144
? N = (144 x 100)/24 = 600

? 540 = H(1 + 20/100)²
? H = (540 x 5/6 x 5/6) = 375 cm

Value of machine 2 years later = Rs. [ 4000 x {(1 - 10)/10)}²]
= Rs. (4000 x 9/10 x 9/10)
= Rs. 3240

Increase in 3 years over 100 = 100 x {1 + 7/(2 x 100)}³
= (100 x 207/200 x 207/200 x 207/200)
= (200 + 7)³ / 80000
= 88869743 / 80000 = 110.8718

Required increase % = (110.8 - 100)% = 10.8%

Let original wages = Rs. 100
Reduced wages = Rs. 50
Increased wages = 150% of Rs. 50 = (150 x 50)/100 = Rs. 75
? Loss = 25%

P = 6q. Thus q is less than p by 5q
? q is less than p by = {(6q - q)/6q} x 100%
= ( 5q/6q) x 100 % = 83¹/_{3 %}