Let 31% of A = 46.5
? (31 x A)/100 = 46.5
? A = (46.5 x 100) / 31 = 150
A% of B + B% of A =AB/100 + AB/100
= 2AB/100 = 2% of AB
? A = 90% of B
? A = (90 x B)/100
Let C% of A = B
Then, (C x A)/100 = B
? [C x {(90 x B)/100}] / 100 = B
? C = (100 x 100) / 90 =111.1
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Let 30% of 80/y =24
? 24y = (30 x 80)/100
? y = (30 x 80)/ (24 x 100) =1
(0.756 x 3/4) = (756/1000) x (3/4) x 100 % = 56.7%
Required number = 80 - 60% of 80
= 80 - (60 x 80)/100
= 32
? 90A/100 = 30B/100 = (30/100) x AC/100
? C = 100 x (100/30) x (90/100) = 300
331/3% = (100/3) /100 = 1/3 =0.33;
4/15 = 0.26
Clearly 0.35>0.33>0.26
? 0.35 is greatest
Let 45 x A = (25 x 900)/100
? A = (25 x 9)/45 = 5
? 0.5/100 of A = 85/100
? A = Rs. (85 / 0.5) = Rs. 170
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