Final Price = Initial price + Initial price x 20/100
= Initial price x (1+20/100)
= Rs.300x(1.2)
= Rs.360
Final Price = 25 x (1 + 20/100) x (1 + 40/100)
=Rs.25 x 1.2 x 1.4
= Rs. 42
Total weight of alloy = 20+20+ 40 = 80g
Weight of tin = 20g
Percentage of tin = 20g/80g x 100
=25%
Concentration of Sulphuric acid = 80%
So in a 100cc, Sulphuric acid = 80cc and water = 20cc
Let x be the amount of water added to make concentration of 50%
?80/(100+x) = 50/100
? 80/(100+x) = 1/2
? x = 60cc
Let Cost Price (CP) = x
Then Selling Price(SP) if he sells at profit = x(1+8%) = 1.08x
and SP, if he sells at loss = x(1-8%) = 0.92%
Given, 1.08%-0.92% = Rs12
0.16x = Rs.12
?x = Rs.75
SP - CP = 480
1.2x - x = 480
?0.2x = 480
?x = 2400
Let the number be y.
Then, 35% of y = 112
( 35 / 100 )y = 112
y = ( 112 x 100 ) / 35
= 320
Let 'x' be the required number
0.75x + 75 =x
? 0.25x=75
? x=75 / 0.25 =300
Sunil's income is less than Mukul's = [(10 / (100 + 10)] × 100 %
= ( 1000 / 110 )%
= 9.09 %
Number of men who can read and write = 150000 × (98 ÷ 100) =147000
Number of men and women who can read and write =294000 × (53 ÷ 100) =155820
Number of women who can read and write 155820 - 147000 = 8820
Thus, out of 144000 women 8820 can read and write.
Required percentage = (8820 × 100) ? 144000 %= 6.125
Let the required number be N.
Then, (16/100) x (40/100) x N = 8
Then, N = (8 x 100 x 100) / (16 x 40)
= 125
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