Apply the law of Fractional Exponents and Laws of Exponents
(am) x (an) = am + n
a-m = 1/am
p0 = 1
and if pX = pY then X will be equal to Y. means X = Y;
(am)n = am x n
(am) x (an) = am + n
am ÷ an = am ? n
Or
am/an = am ? n
Given equation is
2p + 3q = 17 ----------------(i)
2p + 2 - 3q + 1 = 5
? 2p x 22 - 3q x 3 = 5
? 2p x 4 - 3q x 3 = 5
? 4 x 2p - 3 x 3q = 5---------------(ii)
On multiplying Eq. (i) by 3 and adding it, with Eq. (ii), we get
3 x 2p + 3 x 3q = 51
4 x 2p - 3 x 3q = 5
_____________________________
7 x 2p = 56
? 7 x 2p = 7 x 8
? 2p = 8
? 2p = 23
? p = 3
On substituting the value of p in Eq. (i) . we get
23 + 3q = 17
? 8 + 3q = 17
? 3q = 17 - 8
? 3q = 9
? 3q = 32
? q = 2
Here, n = 3 and (n + 1) = 4
? Two hands will coincide at 60n / 11 min past n
? 60 x 3 / 11 min past 3
? 180 /11 min past 3.
? 164/Sub>11 min past 3
New speed = 6/7 of usual speed
Now, time taken = 7/6 of usual time
(7/6 of the usual time) - (usual time) = 10 min
? 1/6 of the usual time = 10 min
? Usual time = 60 min
Square root of (1/4) x (1/49) ÷ (25/121)
= ?(1/4) x (1/49) x (121/25)
= 11 / (2 x 7 x 5)
= 11/70
74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
= (2x2) x (3x3) x (7x7) x (2x3x7)
Least number which should be multiplied to 74088 to make it a Perfect square = 2 x 3 x 7 = 42
Given 1/5 : 1/N = 1/N : 1/1.25
? 1/5 x 1/1.25 = 1/N x 1/N
? N2 = 5 x 1.25 = 6.25
? N = 2.5
Data inadequate
Let their ages be 2x and 3x years
(2x + 12) / (3x + 12) = 11 /15
? 15(2x + 12) = 11(3x + 12)
? 3x = 48
? x = 16
? age of sumit = 3x = 48 years
Given, r = 7 cm, h = 80 cm
Volume = ?r2h = (22/7) x 7 x 7 x 80
= 12320 cm3
∴ The year 700 is not a leap year.
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