Given that
(0.00032)2/5 = (32/100000)2/5
Solve the equation by algebra Law
= (25/105)2/5
= {(2/10)5}2/5
= (2/10)5x2/5
= (1/5)2 = 1/25
Given that, (24x 1/2)? = 256
Apply the law of Fractional Exponents and Laws of Exponents
? (22)? = 28
? 22 x ? = 28
? 2 x ? = 8
? ? = 8/2 = 4
Given, ?10 + ? x = 4
On squaring both sides, we get
10 + ?x = 16
? ?x = 6
Now, cubic on both sides, we get
x = (6)3 = 216
78.9 ÷ (343)1.7 x (49)4.8 = 7?
Apply the law of Fractional Exponents and Laws of Exponents
(am)(an) = am+n
am÷an=am?n
am/an=am?n
(am)n = amn
78.9 ÷ (343)1.7 x (49)4.8 = 7?
? 78.9 ÷ (73)1.7 x (72)4.8 = 7?
? 78.9 ÷ 75.1 x 79.6 = 7?
? 78.9 - 5.1 + 9.6 = 7?
? 718.5 - 5.1 = 7?
? ? = 13.4
Given that, a2x + 2 = 1
Apply the algebra Law,
p0 = 1
? a2x + 2 = a0
Apply the algebra law
pX = pY then X will be equal to Y. means X = Y;
? 2x + 2 = 0
? x = -2/2 = -1
? 3x - 3x - 1 = 18
? 3x - 1(3 - 1) = 18
? 3x - 1(2) = 18
? 3x - 1 = 18/2
? 3x - 1 = 9
? 3x - 1 = 32
Apply the Algebra law,
If aX = aY then X will be equal to Y.
means X = Y;
? x - 1 = 2
? x = 3
Then xx = (3)3 = 27
2x - 1 + 2x + 1 = 2560
2x - 1 + 2x - 1 + 2 = 2560
Apply the Law of Algebra
2x - 1 + 2x - 1 x 2 2 = 2560
? 2x - 1 ( 1 + 22 ) = 2560
? 2x - 1 = 2560/5 = 512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
? 2x - 1 = 29
? x - 1 = 9
? x = 9 + 1 = 10
Given equation is
(10)200 ÷ (10)196
Apply the law of Algebra
am ÷ an = am ? n
= (10)200 - 196
= 104
= 10000
?5 + 2?6 - 1/?5 - 2?6
= ((?5 + 2?6 x ?5 - 2?6 ) - 1)/?5 - 2?6
Apply the formula of Algebra.
( a + b ) x (a - b ) = a2 - b2
= (?(5)2 - (2?6 )2 - 1)/?5 - 2?6
= (?25 - 4 x 6 - 1) /?5 - 2?6
= (?25 - 24 - 1) /?5 - 2?6
= (? 1 - 1 )/?5 - 2?6
= (1 - 1 )/?5 - 2?6
= 0/?5 - 2?6
= 0
? 2x - 1 + 2x + 1 = 320
Apply the law of Algebra
? 2x - 1(1 + 2 2 ) = 320
? 2x - 1(1 + 4 ) = 320
? 2x - 1 x 5 = 320
? 2x - 1 = 64 = 2 x 2 x 2 x 2 x 2 x 2
? 2x - 1 = 26
if pX = pY then X will be equal to Y. means X = Y;
? x - 1 = 6
? x = 7
Given, xyz = 1, ax = b, by = c
Now, b = ax
Apply the law of algebra .
Take the power y of both side equation.
? by= axy
Take the power z of both side equation.
? byz = axyz
? ( by )z = axyz
Replace the by with c and xyz with 1 as per given equation,
? cz = a
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