If any given number (suppose x) is a rational number other than zero, then x0 = 1.
?2n = 64 ? 2n = (64)2
? 2n = (2 × 2 × 2 × 2 × 2 × 2)2
? 2n = (26)2 ? 2n = 26 × 2 = 212
? n = 12.
Given that ,
m = 7 - 4?3
Then I/m = 1/7 - 4?3......................(1)
Now multiply and divide with 7 + 4?3 in Eq. (1)
We will get,
1/m = ( 1/7 - 4?3 ) x ( 7 + 4?3 / 7 + 4?3)
?1/m = ( 7 + 4?3 )/ ( 7 - 4?3 ) x ( 7 + 4?3
?1/m = ( 7 + 4?3 ) / ( 72 - ( 4?3)2 )
?1/m = ( 7 + 4?3 ) / ( 49 - 4 x 4 x 3 )
?1/m = ( 7 + 4?3 ) /49 - 48
?1/m = ( 7 + 4?3 ) / 1
?1/m = 7 + 4?3
? m + 1/m = 14
? ( m + 1/m ) + 2 = 14 + 2 = 16
? (?m + 1/?m)2 = ( m + 1/m )+ 2
? (?m + 1/?m)2 = 16
? (?m + 1/?m)2 = 42
? (?m + 1/?m) = 4
If m and n are natural numbers, then m?n is irrational unless n is mth power of an integer.
Given that, a = 2 + ?
Then, 1/a = 2 - ?3 [ by conjugate property ]
Conjugate law is below,
if x = p + ?
then 1/x = p - ?
Apply the law of algebra in above equation.
Now, we have, a
2 + a
-2
= ( a + 1/a )
2 - 2
= ( 2 + ?
3 + 2 - ?
3)
2 - 2
= (4)
2 - 2 = 16 - 2 = 14
? = 1/ ( 1 + xb - a + xc - a ) + 1/ ( 1 + xa - b + xc - b ) + 1 / ( 1 + xb - c + xa - c )
Apply the law of algebra and solve the given equation.
? ? =1/ ( 1 + xb/xa + xc/xa ) + 1/ ( 1+ xa/xb + xc/xb ) + 1/ ( 1 + xb/xc + xa/xc )
? ? = xa/ ( xa+xb+xc ) + xb/ ( xb + xa+ xc ) + xc/ ( xc+xb+xa )
? ? = ( xa + xb + xc ) / ( xa + xb + xc ) = 1
|
is equivalent to : |
[ ( 2-3 )-4 ]1/4 |
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