Let the cost price of item = ? N
? Marked price of item = N x (100 + 30)/100 = ? 13N/10
Selling price of the item after two successive discount = (13N/10) x[ (100 - 10)/100 x (100 - 10)/100]
= (13N/10) x (90/100) x (90/100) = ? 1053N/1000
Increment in the price of item = [{(1053N/1000) - N} / N] x 100 %
= 53/10 %
= 5.3 %
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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