Let marked price = ? 100
And selling price = ? 80
In condition of 10% loss the cost price of article = (80 x 100)/90 = ? 800/9
According to the question,
When SP = 95, then
? Required profit percentage = [{95 - (800/9)} / (800/9)] x 100 = 55/8
= 6.9% (approx)
Let the original price of pant and shirt be = ? N.
? Cost price of point and shirt = [N x (100 - 25)]/100 = ? 3N/4
And selling price of shirt and pant = (3N/4) x (100 + 40)/100 = (3N/4) x (140/100)
= ? 21N/20
Hence, required percentage
= [(21N/20 - N)/ N] x 100 % = 100 / 20 % = 5%
Here, r = 50% and r1 = 30%
? Gain per cent = [r(100 - r1)/100] - r1
= [50 x (100 - 30)/100] - 30
= 35 - 30 = 5%
Let the marked price of book = ? N
Selling price after 10% discount = 90N/100 = ? 9N/10
Profit = 20%
? Cost price of book = (9N/10) x (100N/120) = ? 3N/4
Hence, required ratio = 3N/4 : N = 3 : 4
Here, r = 30% and r1 = 10%
? Profit per cent = [{r x (100 - r1)}/100] - r1
= [30 x (100 - 10)/100] - 10
= [30 x 90/100] - 10
= 27 -10 = 17%
Here, r = 15% and R = 19%
? Requirement percentage = [(r + R) / (100 - r)] x 100%
= [(15 + 19) / (100 - 15)] x 100% = [(34 x 100) / 85 ] % = 40%
Let cost price = ? 100
And marked price = 100 + 40 = ? 140
Let required discount be R %.
According to the question,
140 x (100 - R)/100 = 100
? 100 - R = (100 x 100) / 140
? R = 100 - (100 x 100) / 140
= (40 x 100) / 140
= 28.5 % (approx)
Here, r = 10% and R = 20%
? Required per cent = (r + R)/(100 - r) x 100 %
= [(10 + 20)/(100 - 10)] x 100% = (30 x 100)/90 %
This shows that the marked price of the item is 100/3 % more
than its cost price.
? Marked price of the article = (450 x 400)/300
= ? 600
? MP of one dozen of pairs of socks = ? 80
? SP of one dozen of pairs of socks
=80 x (100 - 10)/100 = 80 x 90/100= ? 72
Hence, required number of pairs of socks
purchased for ? 24 = (12 x 24)/72 = 4
i. Equivalent single discount to 10 % and 10 % = 10 + 10 - (10 x 10)/100 % = 19 %
ii. Equivalent single discount to 12 % and 8 % = 12 + 8 - (12 x 8)/100 = 20 - 0.96 = 19.04 %
iii. Equivalent single discount to 15 % and 5 % = 15 + 5 - (15 x 5)/100 = 20 - 0.75 = 19.25 %
iv. Equivalent single discount to 20 % = 20 % So, the selling price will be minimum under the scheme iv as in this scheme, the discount is maximum .
Let rate of second discount = r %
MP = ? 3200 , SP = ? 2448 ,
r1 = 10 % and r2 = r %
? y = MP x (100 - r1/100) (100 - r2/100)
? 2448 = [3200 x (100 - 10) x (100 - r)] / (100 x 100)
? (2448 x 100 x 100) / (3200 x 90) = 100 - r
? r = 100 - 85 = 15 %
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