Let k1 and k2 be the roots of quadratic equation .
Given :- k1 = ?2 and k2 = 2 ?2
Sum of the roots = ?2 + 2 ?2 = 3 ?2
Product of the roots = ( ?2 ) ( 2?2 ) = 4
Hence the required quadratic equation is x 2 = (sum of the roots) x + (Product of two roots) = 0
? x 2 - 3 ?2x + 4 = 0.
Given, r1 = 20% and r2 = 20%
? Single discount equal to r1 and r2
= (r1 + r2 - r1 x r2) / 100 %
= (20 + 20 - 20 x 20) / 100
= 40 - 4 = 36%
Let the original price of be N .
? At discount of 20% article costs ? 596
? 596 = (80 x N)/100
? N = (596 x 100)/80
? N = 745
? original price = ? 745
Let amount of electricity bill = ? N
? 4% of N = 13
? (4 x N)/100 = 13
? N = 13 x 25 = ? 325
Here, r1 = 10 %, r2 = 20% and r3 = 30%
? Required discount
= [1 - (1 - r1/100) (1 - r2/100) (1 - r3/100)] x 100%
= [1 - (1 -10/100) (1 - 20/100) (1 - 30/100)] x 100%
= {1 - (9/10) x (4/5) x (7/10)} x 100%
= (1 - 0.504) x 100% = 49.6%
Let the marked price of item = ? N
? {(100 - 14) /100 } of N = 645
? N = (645 x 100)/86 = ? 750
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