Let k1 and k2 be the roots of quadratic equation .
Given :- k1 = ?2 and k2 = 2 ?2
Sum of the roots = ?2 + 2 ?2 = 3 ?2
Product of the roots = ( ?2 ) ( 2?2 ) = 4
Hence the required quadratic equation is x 2 = (sum of the roots) x + (Product of two roots) = 0
? x 2 - 3 ?2x + 4 = 0.
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Given : - Sum of the roots ( k1 + k2 ) = 6
One root k1 = 3 - ?5
? the other root k2 = 6 - ( 3 - ?5) = 3 + ?5
? Product of roots k1k2 = ( 3 - ?5 ) ( 3 + ?5 )
product of roots = 9 - 5 = 4
Hence , the required equation is x2 - (sum of the roots)x + (product of roots) = 0
? x2 - 6x + 4 = 0.
Given, r1 = 20% and r2 = 20%
? Single discount equal to r1 and r2
= (r1 + r2 - r1 x r2) / 100 %
= (20 + 20 - 20 x 20) / 100
= 40 - 4 = 36%
Let the original price of be N .
? At discount of 20% article costs ? 596
? 596 = (80 x N)/100
? N = (596 x 100)/80
? N = 745
? original price = ? 745
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