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Given :- x2 - x - 2 = 0
The given equation is of the form
ax2 + bx + c = 0
Here , a = 1 , b = -1 , c = - 2
Now, D2 = b2 - 4ac = ( -1 )2 - 4 x 1 x ( - 2 )
D = ?9 = 3
So, roots are rational .
Hence, both the roots must be integers.
As per the given above equations , we can say that
?.
?500x + ?402 = 0
? ?500x = - ?402
? x = - ?( 402/500 ) = - ?( 400/500 ) = - 0.9
?. ?360y + ( 200 )1/2 = 0
? ?360y = - ?200
?
y = - ?( 200 / 360 ) = - 0.74
Clearly, we can see that x < y is required answer .
As per the given above question , we have
Let, x = 6 + ?6 + ?6 + ?6 +........
On squaring both sides, we have
x2 = 6 + ?6 + ?6 + ?6 +........
? x2 = 6 + x
? x2 - x - 6 = 0
? x2 - 3x + 2x - 6 = 0
? x( x - 3 ) + 2( x - 3 ) = 0
? ( x - 3 ) ( x + 2 ) = 0
? x = 3 and x ? ?2 because numbers are positive.
Thus , correct answer will be 3 .
Given : - Sum of the roots ( k1 + k2 ) = 6
One root k1 = 3 - ?5
? the other root k2 = 6 - ( 3 - ?5) = 3 + ?5
? Product of roots k1k2 = ( 3 - ?5 ) ( 3 + ?5 )
product of roots = 9 - 5 = 4
Hence , the required equation is x2 - (sum of the roots)x + (product of roots) = 0
? x2 - 6x + 4 = 0.
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