When mistake is done in first degree term, the roots of the equation are -9 and -1.
? Equation
(x+ 1) (x + 9) = x2 + 10x + 9 ...(i)
When mistake is done in constant term, the roots of equation are 8 and 2.
? Equation is
(x - 2) (x - 8) = x2 - 10x + 16 .....(ii)
? Required equation from Eqs. (i) and (ii) is
= x2 - 10x + 9
Also we see in both the cases 1st degree term is same with oposite sign i.e., in such questions we should take data from given conditions and find the correct equation.
Let x% of y = y% of A, then
? xy / 100 = yA/100
? A = (xy/100) x (100/y) = x
Let 371/2% of A = 900
? {(75/2) x A} x 100 = 900
? A = (900 x 2 x 100) / 75 = 2400
So, 621/2% of A = (125/2) x (1/100) x 2400 =1500
Let A - 6% of A = AB.
? (94 x A) / 100 = AB
? B = 0.94
Let original price = Rs. 100
? Increase price = Rs. 160
? Decrease on Rs. 160 = Rs. 60
? Decrease on Rs. 100 = (60/160) x 100 % = 371/2%
?(3.6/100) x 40
= ?1.44 = 1.2
Minimum passing marks = 50 + 50 = 100
Let the total marks = x
Then, 50% of x = 100
? x = (100/50) x 100 = 200
Profit or loss percent = ab/100 %
= (20 x 20)/100 %
= -4%
5% of 50% of 500
= (5/100) x (50/100) x 500
= 12.5
Let the required amount of money be N.
Then, N x 25% = 180 x 121/2%
? N = (180 x 12.5)/25
= ? 90
Monthly income of a person = ? 5000
Increment in income = (30/100) x 5000 = 1500
New income = 5000 + 15000 = ? 6500
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