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Home Aptitude Quadratic Equation Comments

  • Question
  • ?. x 4 ? 227 = 398
    ?. y 2 + 321 = 346


  • Options
  • A. 1
  • B. 2
  • C. 3
  • D. 4

  • Correct Answer
  •  

    Explanation

    According to question ,we can say that
    From equation ?. x4 = 398 + 227 = 625
    ? x4 = 54

    From equation ?. y2 = 346 - 321 = 25
    ? y2 = 52


  • Quadratic Equation problems


    Search Results


    • 1. 
      ?. x 2 ? 7x + 12 = 0
      ?. y 2 + y ? 12 = 0

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 2. 
      ?. x 3 ? 468 = 1729
      ?. y 2 ? 1733 + 1564 = 0

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 3. 
      ?. ? 784x + 1234 = 1486
      ?. ? 1089y + 2081 = 2345

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 4. 
      ?.
      9
      +
      19
      = ?x
      ? x
      ? x

      ?. y5 -
      ( 2 × 14 ) 11/2
      = 0
      ? y

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 5. 
      ?.
      12
      -
      23
      = 5?x
      ? x
      ? x

      ?.
      ? y
      -
      5 ? y
      =
      1
      12
      12
      ? y

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 6. 
      ?. x 2 - 1 = 0
      ?. y 2 + 4y + 3 = 0

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 7. 
      ?. x 3 - 371 = 629
      ?. y 3 - 543 = 788

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 8. 
      ?. 2x 2 + 11x + 12 = 0
      ?. 5y 2 + 27y + 10 = 0

    • Options
    • A. 1
    • B. 2
    • C. 3
    • D. 4
    • Discuss
    • 9. 
      If one root of the quadratic equation 2x 2 + Px + 4 = 0 is 2, find the second root and value of P.

    • Options
    • A. 1, - 6
    • B. 1, 6
    • C. ?1, 6
    • D. ?1, ?6
    • Discuss
    • 10. 
      The roots of the equation 3a2x2 - abx - 2b2 = 0 are

    • Options
    • A. b , - 2b a 3a
    • B. b , 2b a 3a
    • C. - b , - 2b a 3a
    • D. None of these
    • Discuss


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