Mr. Arjun is on tour and he has ? 360 for his expenses. If he exceeds his tour by 4 days, he must cut down his daily expenses by ? 3. For how many days is Mr. Arjun out on tour?

4/?x + 7/?x = ?x;
? 11/?x = ?x
? x = 11
and y² - (11)^5/2/?y = 0
? y² = (11)^5/2/(y)^1/2
? y² x y^1/2 = (11)^5/2
? (y)^5/2 = (11)^5/2
? y = 11
? x = y

x² - 365 = 364
? x² = 364 + 365
? x = ?729 = ± 27
and y - ?324 = ?81 ? y - 18 = 9
? y = 27
So, y ? x or x ? y because y = 27 and x = 27 and - 27.

3x² + 8x + 4 = 0
? 3x² + 6x + 2x + 4 = 0
? 3x(x + 2) + 2(x + 2) = 0
? (x + 2) (3x + 2) = 0
? x = - 2, - 2/3
and 4y² - 19y + 12 = 0
? 4y² - 16y - 3y + 12 = 0
? 4y(y - 4) -3(y - 4) = 0
? (y - 4) (4y - 3) = 0
? y = 4, 3/4
Hence, y > x or x < y

x² - x - 12 = 0
? x² - 4x + 3x - 12 = 0
? x(x - 4) + 3 (x - 4) = 0
? (x - 4) (x + 3) = 0
? x = - 3, 4
and y² + 5y + 6 = 0
? y² + 3y + 2y + 6 = 0
? y(y + 3) + 2(y + 3) = 0
? (y + 3) (y + 2) = 0
? y = - 3, - 2
? x ? y
[? x = - 3 and y = - 3, so x = y and x = 4 and y = - 2, hence x > y]

x² - 8x + 15 = 0
? x² - 5x - 3x + 15 = 0
? x(x - 5) -3(x - 5) = 0
? (x - 5) (x - 3) = 0
? x = 5, 3
and y² - 3y + 2 = 0
? y² - 2y - y + 2 = 0
? y(y - 2) -1(y - 2) = 0
? (y -2) (y - 1) = 0
? y = 2, 1
? x > y

As per the given above question , we have
Let k₁ and k₂ be the roots of quadratic equation .
One root is k₁ = ?5
So the other root is k₂ = ? ?5
? Sum of the roots = k₁ + k₂ = ?5 + ( -?5 ) = 0
and product of the roots = k₁ × k₂ = ? (?5) (- ?5) = ?5
? Required equation is x² - (sum of the roots)x + (product of the roots) = 0
? x² - 5 = 0.

According to question ,we can say that
From equation ?. x² ? 19x + 84 = 0
? x² ? 7x ? 12x + 84 = 0
? (x ? 7)(x ? 12) = 0
? x = 7, 12
From equation ?. y² ? 25y + 156 = 0
? y² ? 13y ? 12y + 156 = 0
? (y ? 13)(y ? 12) = 0
? y =12, 13
? x ? y
From above it is clear that x ? y is correct answer .