Let the roots be ? and ? .
Then, ? + ? = 8 ......(i)
? - ? = 4 ..(ii)
On solving Eqs. (i) and (ii), we get
? = 6, ? = 2
? Required equation is
x2 - (? + ?) x + (? ?) = 0
? x2 - (6 + 2)x + 6 x 2 = 0
? x2 - 8x + 12 = 0
The number of pieces of chocolate left with Manju
= 1- [(1/4) + (1/3) + (1/6)
= 1 - (3 + 4 + 2)/12
= 1 - 9/12 = (12 - 9) / 12
= 3/12
Third power of 4 = 43 = 4 × 4 × 4 = 64
Total number of cards n(S) = 52
Number of red cards n(E) = 26
? P(E) = n(E)/n(S) = 26/52 = 1/2
Given Exp. = [(4 x 5 x 6) + (5 x 6) + (2 x 6) + (2 x 3)] / [(2 x 3 x 4 x 5 x 6)]
= 168 / (24 x 30)
= 7 / 30
Speeds (in m/sec) of A and B are
9 / 2 * 5 / 18 = 5 / 4 and 6 * 5 / 18 = 5 / 3, respectively.
A has a start of 190 m.
So, A has to run 1000 - 190 = 810 m, while B 1000 m.
Time taken by B to cover 1000 m = 3 5 × 1000 = 600 seconds.
In this time, A covers 5 × 600 / 4 = 750 m.
So, B reaches the winning post while A remains 810 - 750 = 60 m behind.
? B wins by 60 m.
Let 30% of 80/y =24
? 24y = (30 x 80)/100
? y = (30 x 80)/ (24 x 100) =1
Let the radius of the park be r, then
?r + 2r = 288
(? + 2)r = 288
? [(22/7) + 2]r = 288
? r = (288 x 7)/36 = 56
? Area of the park = (1/2)?r2
= (1/2) x (22/7) x 56 x 56
= 4928
1178.999 x 25.0001 - ?? x 16.0011 = 29075
? 1179 x 25 - ?? x 16 = 29075
? 29475 - ?? x 16 = 29075
? ?? x 16 = 29475 - 29075 = 400
? ?? = 25
? ? = 25 x 25 = 625
So, 96 is wrong.
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