Given that, the roots of the quadrictic equation are 3 and -1.
Let ? = 3 and ? = -1
Sum of roots = ? + ? = 3 - 1 = 2
Products of roots = ? . ? = (3) (-1) = -3
? Required quadric equation is
x2 - (? + ?)x + ? ? = 0
? x2 - (2)x + (-3) = 0
? x2 - 2x - 3 = 0
Given equation is
x2 + 2(k - 4)x + 2k = 0
On comparing with ax2 + bx + c = 0
Here, a = 1, b = 2(k -4), c = 2k
Since, the root are equal, we have D = 0.
b2 - 4ac = 0
? 4(k - 4)2 - 8k = 0
4(k2 + 16 - 8k) - 8k = 0
? 4k2 + 64 - 32k - 8k = 0
? 4k2 - 40k + 64 = 0
? k2 - 10k + 16 = 0
? k2 - 8k - 2k + 16 = 0
? k(k - 8) -2 (k - 8) = 0
? (k - 8) (k - 2) = 0
Hence, the value of k 8 or 2.
Given quadratic equation is
7y2 - 50y + k = 0
If one root is 7, then it will satisfy the equation i.e putting y = 7 in equation
7 x (7)2 - 50 x 7 + k = 0
? 7 x 49 - 350 + k = 0
? 343 - 350 + k = 0
? k = 7
Given equation is
x2 - 3x + 1 = 0 ? x2 + 1 = 3x
? x2 + 1/x = 3
? x2/x + 1/x = 3
? x + 1/x = 3
( | x + |
|
) | 2 | - |
|
( | x - |
|
) | = 4 is : |
x | 2 | x |
Let, the breadth of the rectangular plot be x m. Then the length of rectangular plot = (x + 8) m
? Area = Length × Breadth = x(x + 8)m2 But the area of the plot is given to be 308 m2
? x( x + 8 ) = 308 ? x2 + 8x - 308 = 0
? x2 + 22x - 14x - 308 = 0
? x( x + 22 ) - 14 ( x - 22 ) = 0
? ( x + 22 ) ( x - 14 ) = 0
? x = 14, -22
But, x = ?22 is not possible, since breath cannot be negative
? x = 14
Hence the breadth of the rectangular plot = 14 m Length of the rectangular plot = (14 + 8) m = 22 m.
Given equation is 4x2 - 19x + 12 = 0
Let given equation having the roots 1/? and 1/?,
Then required equuation is
12x2 - 19x + 4 = 0
Let ? and ? be the roots of the quadratic equation 2x2 - 11x + 5 = 0
? ? + ? = -(-11)/2 = 11/2 ...(i)
and ?? = 5/2
Now, (? - ?)2 = (? + ?)2 - 4??
= (11/2)2 - 4(5/2) = 121/4 - 20/2
= 121 - 40/4 = 81/4 = (9/2)2
? Difference of roots = (? - ?) = 9/2 = 4.5
Let ? = 2, ? = 1/4
Then, ? + ? = 2 + 1/4 = 9/4
?? = 2.1/4 = 1/2
Equation having the roots ? and ? is
x2 - (? + ?)x + ? ? = 0
? x2 - 9/4x + 1/2 = 0
? 4x2 - 9x + 2 = 0
Since, p and q are the roots of the equation x2 + px + q = 0
Then, p + q = - p
and pq = q
Now, pq = q
? p = 1
Putting the value of p in p + q = - p, we get
1 + q = - 1
? q = - 2
We know that, AM ? GM
? ?a + 1/?a ? 2
Here, ?x2 - x + 1 + 1/?x2 - x + 1 ? 2
? 2 - x2 ? 2
? x2 ? 0
? x = 0
Hence, the given equation has only one solution.
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