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- Question
- ?. 4x + 7y = 209
?. 12x ? 14y = ? 38
Options- A. 1
- B. 2
- C. 3
- D. 4
- Correct Answer
-
ExplanationAccording to question ,we can say that
?. 4x + 7y = 209 ...............( 1 )
?. 12x ? 14y = ? 38 .................... ( 2 )
Multiplying (1) by (2):
8x + 14y = 418 ................(3)
Adding (2) and (3):
20x = 380 ? x = 19
Substituting the value of x in (1), we get
76 + 7y = 209
? 7y = 133 ? y = 19
From above equations it is clear that x = y is correct answer . - 1. Construct a quadratic equation whose roots have the sum = 6 and product = ?16.
Options- A. x2 - 6x - 16 = 0
- B. x2 + 6x - 16 = 0
- C. x2 - ?3x - 16 = 0
- D. None of these Discuss
- 2. One root of the quadratic equation x2 - 5 x + 6 = 0 is 3. Find the other root.
Options- A. 2
- B. ?2
- C. 1
- D. ?1 Discuss
- 3. If one roots of the equation x 2/a = x/b + 1/c = 0 is reciprocal of the other, then which one of the following is correct?
Options- A. a = b
- B. b = c
- C. ac = 1
- D. a = c Discuss
- 4. If 2x 2 - 7xy + 3y 2 = 0, then the value of x : y is
Options- A. 3 : 2
- B. 2 : 3
- C. 3 : 1 and 1 : 2
- D. 5 : 6 Discuss
- 5. If [a + (1/a)] 2 = 3 , what is the value of a 3 + (1/a) 3?
Options- A. 10?3/3
- B. 0
- C. 3?3
- D. 6?3 Discuss
- 6. ?. 18x 2 + 18x + 4 = 0
?. 12y 2 + 29y + l4 = 0
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 7. ?. 8x 2 + 6x = 5
?. 12y 2 ? 22y + 8 = 0
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 8. ?. 16x 2 + 20x + 6 = 0
?.10y 2 + 38y + 24 = 0
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 9. ?. 17x 2 + 48x = 9
?.13y 2 = 32y ?12
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 10. The roots of the equation a2x2 - 3abx + 2b2 = 0 are
Options- A. 2b , - b a a
- B. 2b , b a a
- C. - 2b , - b a a
- D. None of these Discuss
Quadratic Equation problems
Search Results
Correct Answer: x2 - 6x - 16 = 0
Explanation:
Given that :- sum of the roots = 6
And Product of two roots = -16
The required quadratic equation is x2 ? (sum of the roots) x + (product of the roots) = 0
? x2 - 6x - 16 = 0
Correct Answer: 2
Explanation:
The given equation is
x2 - 5x + 6 = 0 ? x 2 - 2x - 3x+ 6 = 0
? x( x - 2 ) - 3( x - 2 ) = 0
? ( x - 2 ) ( x - 3 ) = 0
? x - 2 = 0 or x - 3 = 0
? x = 2 or x = 3
Thus, the other root of the given quadratic equation is 2.
Correct Answer: a = c
Explanation:
Given quadric equation is
x2 + x/b + 1/c = 0 ...(i)
Now, by condition the roots of the Eq.(i) are ? and 1/?.
Now,product of roots = (1/c) / (1/a)
? ?.(1/?) = a/c
? c = a
which is the required relation.
Correct Answer: 3 : 1 and 1 : 2
Explanation:
2x2 - 7xy + 3y2 = 0
? 2x2 - 6xy - xy + 3y2 = 0
? 2x(x - 3y) - y(x - 3y) = 0
? (2x - y) (x - 3y) = 0
Either, 2x - y = 0 ? 2x = y
? x/y = 1/2
or x - 3y = 0
? x = 3y ? x/y = 3/1
Correct Answer: 0
Explanation:
[a + (1/a)]2 = 3
Taking square roots both sides, we get
a + (1/a) = ?3
On cubing both sides, we
[a + (1/a)]3 = (?3)3
? a3 + 1/a3 + 3.a.1/[a(a + 1/a)] = 3 ?3
? a3 + 1/a3 + 3?3 = 3?3
? a3 + 1/a3 = 0
Correct Answer: 4
Explanation:
Correct Answer: 3
Explanation:
Correct Answer: 2
Explanation:
Correct Answer: 1
Explanation:
Correct Answer: 2b , b a a
Explanation:
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