Let us assume the present age of father = F year and Son's present age = S years
According to question, 5 years ago,
Father's age = F - 5 and Son's age = S - 5.
According to the question,
The age of the father 5 years ago was 5 times the age of his son.
F - 5 = 5(S - 5)
F - 5 = 5S - 25.....................(1)
At present the father's age is 3 times that of his son.
F = 3S.................................(2)
Put the value of F from equation (2) in equation (1), we will get
? 3S - 5 = 5S - 25
? 25 - 5 = 5S - 3S
? 20 = 2S
? 10 = S
? S = 10.
Put the value of S in Equation (2). we will get,
F = 3S = 3 x 10 = 30
So the present Age of Father = 30.
Sum of four number = ( 15 x 3 + 19 ) = 64
Sum of last three number = ( 16 x 3 ) = 48
? first number = ( 64 ? 48 ) = 16
Temperature of last day = Sum of temperature of 7 days - sum of temperature of first 6 days.
= ( 7 x 28.5 ) - [( 3 x 27 ) + ( 3 x 29 )]
=31.5
? Temperature of last day = 31.5
Average = ( sum of consumption of petrol in first 7 months + sum of consumption of petrol in last 5 months. ) / 12
Average = ( 110 x 7 + 86 x 5 ) / 12
=(1200 / 12 = 100 liters
Let the average for first 11 innings is y
From question
11y + 90 = (y - 5) x 12
? y = 150
? Average after 12th inning = (150 - 5)= 145
Present age of P = [(49 x 5 ) - (4 x 45 + 4 x 5 ) ] years
= 45 years.
Let the numbers be 2y, y and 4y
? Average = (2y + y + 4y)/3
? 7y/3 = 56
? y = (3 x 56) / 7 = 24
Hence , the number in order are 48, 24 and 96
Sum of 7 numbers = sum of first 3 numbers + N4 + sum of last 3 numbers.
(23 x 3) + N4 + (42 x 3) = 235
? N4 = 40
? 4th number = 40
Here initial average = 7
As we know that, if all the numbers are multiple by a certain number, then their average must be a multiple of that number.
? New average = 7 x 12 = 84
Total correct weight = (40 x 60) - 36 + 33 = 2400 - 3 = 2397 kg
? Required average weight = 2397/60 = 39.95 kg
Let total journey = y km
Total time taken = time taken during 60% of distance + time taken during 20% of distance + time taken in remaining distance
= [( 60y / 100 ) / 30] + [( 20y / 100 ) / 20] + [( 20y / 100 ) / 10]
= ( y / 50 + y / 100 + y / 50 )hrs
= y/20 hours.
Average speed = total distance traveled / total time taken.
= [y / ( y/20 )] km/hr
=20 km/hr.
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