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- Question
- 36 men can complete a piece of work in 18 days. In how many days will 27 men complete the same work?
Options- A. 24
- B. 23
- C. 34
- D. 39
- Correct Answer
- 24
Explanation
- 1. A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time.
If he had not engaged the additional men, how many days behind schedule would it be finished?
Options- A. 7
- B. 18
- C. 12
- D. None Discuss
- 2. A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
Options- A. 4
- B. 9
- C. 14
- D. 7 Discuss
- 3. If 20 men can build a wall 56 meters long in 6 days , what length of a similar wall can be built by 35 men in 3 days?
Options- A. 40
- B. 43
- C. 48
- D. 49 Discuss
- 4. 2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in.
Options- A. 18
- B. 21
- C. 34
- D. 39 Discuss
- 5. If 40 men can make 30 boxes in 20 days, How many more men are needed to make 60 boxes in 25 days?
Options- A. 20
- B. 24
- C. 27
- D. 28 Discuss
- 6. Some persons can do a piece of work in 12 days. Two times the number of such persons will do half of that work in :
Options- A. 16
- B. 12
- C. 8
- D. 3 Discuss
- 7. If 36 men can do a piece of work in 25 hours, in how many hours will 15 men do it?
Options- A. 45
- B. 55
- C. 60
- D. 72 Discuss
- 8. The Fourth term of an Arithmetic Progression is 37 and the Sixth term is 12 more than the Fourth term. What is the sum of the Second and Eight terms?
Options- A. 54
- B. 64
- C. 74
- D. 84 Discuss
- 9. How many 3-digits numbers are completely divisible by 6?
Options- A. 149
- B. 150
- C. 151
- D. 166 Discuss
- 10. On March 1st 2016 , sherry saved ? 1. Everyday starting from March 2nd 2016, he save ?1 more than the previous day . Find the first date after March 1st 2016 at the end of which his total savings will be a perfect square.
Options- A. 17th March 2016
- B. 18th March 2016
- C. 26th March 2016
- D. None of these Discuss
Unitary Method problems
Search Results
Correct Answer: None
Explanation:
Correct Answer: 9
Explanation:
Correct Answer: 49
Explanation:
Correct Answer: 21
Explanation:
Correct Answer: 24
Explanation:
Correct Answer: 3
Explanation:
Correct Answer: 60
Explanation:
Correct Answer: 74
Explanation:
Let us assume the first number is a and common difference is d.
According to question,
4th term of A.P = 37
a + ( n - 1 ) x d = 37
Put the value of a , n and d, we will get,
a + (4 - 1 ) x d = 37
a + 3d = 37..................(1)
sixth term is 12 more than the fourth term,
6th term = 12 + 4th term
a + ( n - 1 ) x d = 12 + 37
a + ( 6- 1 ) x d = 39
a + 5d = 39................(2)
subtract the equation (1) from (2)
a + 5d - a - 3d = 39 - 37
5d - 3d= 2
2d = 2
d = 1
Put the value of d in equation (1), we will get
a + 3 x 1 = 37
a = 37 - 3
a = 34
Second term = a + (n - 1) x d = 34 + (2 - 1) x 1 = 34 + 1 = 35
Six term = a + (n - 1) x d = 34 + (6 - 1) x 1 = 34 + 5 = 39
Sum of Second and Six term = 35 + 39 = 74
Sum of Second and Six term = 74
Answer is 74.
Correct Answer: 150
Explanation:
First 3-digit number divisible by 6 is 102 and last 3-digit number divisible by 6 is 996.
Difference between two consecutive numbers divisible by 6 is 6.
So 3-digit numbers divisible by 6 are 102,108,114, ......., 996.
This is an Arithmetic Progression in which a = 102, d = 6 and l = 996.
where a = First Number , l = Last Number and d = difference of two consecutive numbers.
Let the number of terms be n. So Last term = tn
Then tn = 996
Use the formula for n terms of arithmetic progression.
? a + ( n - 1) x d = 996
? 102 + (n - 1) x 6 = 996
? 6(n - 1) = 894
? (n - 1) = 149
? n = 150
? Numbers of terms = 150
Correct Answer: None of these
Explanation:
According to the question,
Every day adding 1 rs extra to previous day.
Let us assume after n day, total saving will become perfect square.
1 + 2 + 3 + 4 + 5 + 6 +.......................+ tn.
Apply the algebra A.P formula,
sum of total rupees after n days = n(n+1)/2
Hit and trail method, Put the value of n = 2 , 3 , 4, 5 .... and so on to get the perfect square.
If n = 2
n(n+1)/2 = 2 x 3 / 2 = 3 which is not perfect Square.
If n = 3
n(n+1)/2 = 3 x 4 / 2 = 6 which is not perfect Square.
If n = 4
n(n+1)/2 = 4 x 5 / 2 = 10 which is not perfect Square.
If n = 5
n(n+1)/2 = 5 x 6 / 2 = 15 which is not perfect Square.
If n = 6
n(n+1)/2 = 6 x 7 / 2 = 21 which is not perfect Square.
If n = 7
n(n+1)/2 = 7 x 8 / 2 = 28 which is not perfect Square.
If n = 8
n(n+1)/2 = 8 x 9 / 2 = 36 which is perfect Square.
n(n+1)/2 should be a perfect square . The first value of n when this occurs would be for n = 8. thus , on the 8th of March of the required condition would come true.
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