As we know from the given question,
P men working P hours per day in P days can do P units of a work.
1 men working P hours per day in P days can do P / P units of a work.
1 men working 1 hours per day in P days can do P /P x P units of a work.
1 men working 1 hours per day in 1 days can do P /P x P x P units of a work.
Q men working 1 hours per day in 1 days can do P x Q /P x P x P units of a work.
Q men working Q hours per day in 1 days can do P x Q x Q /P x P x P units of a work.
Q men working Q hours per day in Q days can do P x Q x Q x Q/P x P x P units of a work.
Q men working Q hours per day in Q days can do Q3/P2 units of a work.
According to question ,
39 persons can repair a road by working 5 hours a day in 12 days.
1 persons can repair a road by working 5 hours a day in 12 x 39 days.
1 persons can repair a road by working 1 hours a day in 12 x 39 x 5 days.
30 persons can repair a road by working 1 hours a day in 12 x 39 x 5 / 30 days.
30 persons can repair a road by working 6 hours a day in 12 x 39 x 5 / 30 x 6 days.
30 persons can repair a road by working 6 hours a day in 2 x 39 x 5 / 30 days.
30 persons can repair a road by working 6 hours a day in 39 x 1 / 3 days.
30 persons can repair a road by working 6 hours a day in 13 days.
3 pumps, can empty a tank in 2 days by working 8 hours a day.
1 pumps, can empty a tank in 2 days by working 8 x 3 hours a day.
1 pumps, can empty a tank in 1 days by working 8 x 3 x 2hours a day.
4 pumps, can empty a tank in 1 days by working 8 x 3 x 2 / 4 hours a day.
4 pumps, can empty a tank in 1 days by working 2 x 3 x 2 hours a day.
4 pumps, can empty a tank in 1 days by working 12 hours a day.
Here , Cost of 1 chair = Rs. 214 and cost of one table = Rs. 937 .
? Cost of 6 dozen chairs = 6 × 12 × 214 = Rs. 15408
and cost of 4 dozen tables = 4 × 12 × 937 = Rs. 44976
? Total cost = 15408 + 44976
Total cost = Rs. 15408 + 44976 = Rs. 60384
Total cost of chairs and tables ? Rs. 60000 (Approximately)
As per the given question ,
Food of 150 men for 45 days = 150 × 45 = 6750 unit
After 10 days , Food of 150 men for 150 × 10 = 1500 unit
And after 10 days remaining men = 150 - 25 = 125
and remaining food = 6750 - 1500 = 5250 unit
Let D be the number of days for which the remaining food .
So, 125 × D = 5250
? D = 5250 /125 = 42 days
Let required amount of coal be y metric tonnes
9 engines consumes 24 metric tonnes of coal in 8 hours a day.
More engines, more amount of coal (direct proportion)
If 3 engines of first type consume 1 unit, then 1 engine will consume 1/3 unit which is its the rate of consumption.
If 4 engines of second type consume 1 unit, then 1 engine will consume 1/4 unit which is its the rate of consumption
More rate of consumption, more amount of coal (direct proportion)
More hours, more amount of coal(direct proportion)
Now we have , 9 × ( 1 / 3 ) × 8 × y = 8 × ( 1 / 4 ) × 13 × 24
? 3 × 8 × y = 8 × 6 × 13
? 3 × y = 6 × 13 ? y = 2 x 13 = 26 metric tonnes
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