Let man's 1 day's work = 1/m
and boy's 1 day's work = 1/n
1 day's work man and boy = 1/24
Man's 6 day's work = 6/m
Now, for 20 days, both man and boy do the work and for last 6 days, only man does the work.
According to the question,
1/m + 1/n = 1/24
? 20(1/m + 1/n) + 6/m = 1
? 20 x (1/24) + 6/m = 1
? 6/m = (1 - 20/24) = 4/24 = 1/6
? 1/n = 1/36
Now from eq. (i)
1/m + 1/n = 1/24
1/36 + 1/n = 1/24
? 1/n = (1/24) - (1/36) = 1/72
Hence, the boy alone can do the work in 72 days.
? a / b = 2/3 and 2 / a = 1/2
? a/b x 2/a = 2/3 x 1/2
? 2/b = 1/3
? b = 6
0.6 x a = 0.09 x b
? a/b = 0.09 / 0.06 = 9 / 60 = 3 / 20 = 3 : 20
Let a/3 = b/8 = K
Then, a = 3K, b = 8K
? (a + 3) / (b + 8) = (3K + 3) / (8K + 8)
= [3( K + 1)] / [8(K+1)] = 3/8
? ( a + 3 ) : (b + 8) = 3 : 8
Series pattern +15, + 30, +60, +120
? Missing term = 49 + 60 = 109
777777 / 11 = 70707.
NA
According to the question,
1728 = 1331(1 + R/100)3
1728/1331 = (1 + R/100)3
? (12/11)3 = (1 + R/100)3
? 1 + R/100 = 12/11
? R/100 = (12/11) - 1 = 1/11
? R = 100/11= 9.09%
Here, M + N = 10 and MN = 20
According to the question,
(1/M) + (1/N) = (M + N) / MN = 10/20 = 1/2
Time = distance / speed
=110 / {60 x 18/5} = 6.6 sec.
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