? For 50 students, food is sufficient for 45 days.
? For 1 students, food is sufficient for 45 x 50 days.
? For 75 students, food is sufficient for (45 x 50)/75 days i.e., for 30 days .
Let the number of soldiers transferred be N
Now, the food would last for 25 days for (2000 - N) soldiers.
Less men, More days (indirect proportion)
25 : 20 : : 2000 : (2000 - N)
? 2000 - N = (2000 x 20)/25
? 2000 - N = 1600
? N = 2000 - 1600 = 400
Let the required number of flies be N.
More spiders, More flies (Direct proportion)
More time, More flies (Direct proportion)
? 10 x 10 x N = 200 x 200 x 10
? N = (200 x 200 x 10)/(10 x 10) = 4000 flies
M1 = 12 H1 = 16, W1 = 33600
M2 = 18, H2 = 12, W2 = ?
By formula, M1H1/W1 = M2H2/W2
(12 x 16)/33600 = (18 x 12)/W2
? W2 = (33600 x 18)/16
? W2 = 2100 x 8
? W2 = 37800
? For 1000 men, provision lasts for 48 days.
? For 1 men, provision lasts for (48 x 1000) days.
? For (1000 + 600) men, provision will last for (48 x 1000)/1600 days.
? Required number of days = (48 x 1000)/1600 = 3 x 10 = 30
Here M1 = 30, D1 = 16,
T1 = 9, M2 = 36 and T2 = 8
By formula, M1D1T1 = M2D2T2
30 x 16 x 9 = 36 x D2 x 8
? D2 = (30 x 16 x 9)/(36 x 8) = 15 days
Let the required number of days be N.
More men, Less days (indirect proportions)
Soldiers 90 : 72
Ratio 9 : 10
N = (72 x 54 x 10)/(90 x 9) = 48 days
3 men ? 6 boys
? 1 man ? 2 boys
? 4 men + 4 boys ? 4 men + 2 men = 6 men
? 3 men can do a work in 18 days.
? 1 man can do a work in 18 x 3 days.
? Required number of days = (18 x 3)/6 = 9 days
1 women ? 1/2 man
10 men + 8 women ? 10 men + 4 men = 14 men
4 men + 6 women ? 4 men + 3 men = 7 men
More men, Less days (Indirect proportion) 7 : 14 : : 5 : N
? N = (14 x 5)/7 = 10 days
1 man can finish the work in (8 x 12) = 96 days
1 woman can finish the work in (4 x 48) = 192 days
1 child can finish the work in (10 x 24) = 240 days
1 man's 1 day's work = 1/96
1 women's 1 day's work = 1/192
1 child's 1 day's work = 1/240
(10 men + 4 women + 10 children)'s 1 day's work = (10/96 + 4/192 + 10/240)
= (5/48 + 1/48 + 1/24)
= (5 + 1 + 2)/48)
= 8/48 = 1/6
Hence, they will finish the work in 6 days.
Work done = 1/3
Remaining work = 1 - (1/3) = 2/3
Let the number of more men to be employed be N.
More work, More men (Direct proportion)
More days, Less men (Indirect proportion)
Work 1/3 : 2/3
Days 25 : 20
? 1/3 x 25 x (20 + N) = 2/3 x 20 x 20
? (20 + N) = 800/25 = 32
? N = 32 - 20 = 12
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