Suppose that y men had provisions for D days .Then y men had provisions for ( D - 10 ) days .
[ y - ( y/5 ) ] men had provisions for D days .
According to question ,
? y( D - 10 ) = ( 4y/5 ) x D ? 5Dy - 50y = 4Dy
? Dy - 50y = 0 ? y( D - 50 ) = 0 ? D = 50 days
Hence required answer is 50 days .
Given in the question,
If radius is 14 cm then rope can make 70 rounds.
If radius is 1 cm then rope can make 70 x 14 rounds.
If radius is 20 cm then rope can make 70 x 14 / 20 rounds.
If radius is 20 cm then rope can make 7 x 7 rounds.
If radius is 20 cm then rope can make 49 rounds.
A person completes 5/8 part of the project in 10 days.
A person completes the project in 10/5/8 days.
A person completes the project in 10 x 8 /5 days.
A person completes the project in 2 x 8 days.
A person completes the project in 16 days.
Given in the question,
Price of 6 toys is Rs. 264.37.
? Price of 1 toys is Rs. 264.37/ 6 .
? Price of 5 toys is Rs. 264.37 x 5 / 6 .
? Price of 5 toys is Rs. 44 x 5 .
? Price of 5 toys is Rs. 220.
According to given question,
Since 900 books are bonded in 10 days by 18 binders.
? 1 books are bonded in 10 days by 18 / 900 binders.
? 1 books are bonded in 1 days by 18 x 10 / 900 binders.
? 660 books are bonded in 1 days by 18 x 10 x 660 / 900 binders.
? 660 books are bonded in 12 days by 18 x 10 x 660 / 12 x 900 binders.
? 660 books are bonded in 12 days by 18 x 10 x 55 / 900 binders.
? 660 books are bonded in 12 days by 18 x 55 / 90 binders.
? 660 books are bonded in 12 days by 55 / 5 binders.
? 660 books are bonded in 12 days by 11 binders.
A certain industrial loom weaves 0.128 meters of cloth in 1 second.
A certain industrial loom weaves 1 meters of cloth in 1/0.128 second.
A certain industrial loom weaves 25 meters of cloth in 25 x 1/ 0.128 second.
A certain industrial loom weaves 25 meters of cloth in 195.312 second.
Given in the question,
Let k be the men there originally .
Work done by y men can finish = 100 days
If there were 10 men less, it would take more days finish the work in 10 days
i.e. ( k - 10 ) = 110
According to question ,
k × 100 = ( k - 10 ) × 110
? 100k = 110k - 1100 ? 10k = 1100 ? k = 110
Therefore , 110 men were there originally .
According to question,
A shadow of length 40.25 meters is build for a height of 17.5 meters.
A shadow of length 1 meters is build for a height of 17.5 /40.25 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 28.75 /40.25 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 2875 /4025 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 575 /805 meters.
A shadow of length 28.75 meters is build for a height of 17.5 x 115/161 meters.
A shadow of length 28.75 meters is build for a height of 12.5 meters.
Since 6 identical machines in 1 minute can produce a total of 270 bottles.
? 1 identical machines in 1 minute can produce a total of 270 / 6 bottles.
? 10 identical machines in 1 minute can produce a total of 270 x 10 / 6 bottles.
? 10 identical machines in 4 minute can produce a total of 270 x 10 x 4 / 6 bottles.
? 10 identical machines in 4 minute can produce a total of 45 x 10 x 4 bottles.
? 10 identical machines in 4 minute can produce a total of 1800 bottles.
For 50 students, food is sufficient for 45 days
? For 1 student, food is sufficient for 45 x 50 days
and for 75 students, food is sufficient for (45 x 50)/75 days. i,e., for 30 days.
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