Suppose that y men had provisions for D days .Then y men had provisions for ( D - 10 ) days .
[ y - ( y/5 ) ] men had provisions for D days .
According to question ,
? y( D - 10 ) = ( 4y/5 ) x D ? 5Dy - 50y = 4Dy
? Dy - 50y = 0 ? y( D - 50 ) = 0 ? D = 50 days
Hence required answer is 50 days .
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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