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- Question
- 840.003 ÷ 23.999 =?
Options- A. 47
- B. 8
- C. 35
- D. 18
- Correct Answer
- 35
Explanation? = 840.003 ÷ 23.999
Here one number is increased and other is decreased to their nearest whole number
= 840 ÷ 24 = 35 - 1. 16.003 x 27.998 - 209.010 =?
Options- A. 150
- B. 200
- C. 75
- D. 240 Discuss
- 2. 125.009 + 69.999 + 104.989 =?
Options- A. 420
- B. 300
- C. 285
- D. 415 Discuss
- 3. The average weight of the students in four sections A, B, C and D is 60 kg. The average weight of the students of A, B, C and D individually are 45 kg, 50 kg, 72 kg and 80 kg, respectively. If the average weight of the students of section A and B together is 48 kg and that of B and C together is 60 kg. What is the ratio of the number of the students in sections A and D?
Options- A. 12 : 7
- B. 4 : 3
- C. 3 : 2
- D. 8 : 5 Discuss
- 4. 5 yr ago, the average age of Rashmi and Surbhi was 20 yr, Now, the average age of Rashmi, Surbhi and Meeta is 30 yr. What will be the age of Meeta after 15 yr.?
Options- A. 35 yr
- B. 55 yr
- C. 39 yr
- D. 67 yr Discuss
- 5. The average weight of 4 men, A, B, C and D is 67 kg. The 5th man E is included and the average weight decreses by 2 kg. A is replaced by F. The weight of F is 4 kg more then E . Average weight decreases because of the replacement of A and now the average weight is 64 kg. Find the weight of A.
Options- A. 78 kg
- B. 66 kg
- C. 75 kg
- D. 58 kg Discuss
- 6. 6885.009 - 419.999 - 94.989 =?
Options- A. 6650
- B. 6830
- C. 6370
- D. 6200 Discuss
- 7. 503 x 201=?
Options- A. 101100
- B. 1000000
- C. 110000
- D. 100003 Discuss
- 8. (2/3) x (6/8) x (2/3) x (3/4) =?
Options- A. 0.25
- B. 0.5
- C. 1.45
- D. 11.8 Discuss
- 9. 15 7/ 8 x 23 1/ 5 + 3 4/ 5 x 5 1/ 8 =?
Options- A. 360
- B. 350
- C. 370
- D. 385 Discuss
- 10. 2 3/ 5 x 15/26 x 283.75 =?
Options- A. 440
- B. 435
- C. 410
- D. 425 Discuss
Approximation problems
Search Results
Correct Answer: 240
Explanation:
? = 16.003 x 27.998 - 209.010
? ? 16 x 28 - 210 = 448 - 210
? = 238 ? 240
Correct Answer: 300
Explanation:
125.009 + 69.999 + 104.989 = ?
Lets assume, each value is approximated to nearest whole number
? ? ? 125 + 70 + 105
? ? ? 300
Correct Answer: 4 : 3
Explanation:
Let number of students in the sections
A, B, C and D be a, b, c and d respectively.
Then, total weight of students of sections A = 45a
Total weight of students of section B = 50b
Total weight of students of section C = 72c
Total weight of students of section D = 80d
According to the question,
Average weight of students of sections of A and B = 48 kg
? (45a + 50b)/(a + b) = 48
? 45a +50b = 48a + 48b
? 3a = 2b
? 15a = 10b
And average weight of students of sections B and C = 60 kg
? 50b + 72c = 60(b + c)
? 10b = 12c
Now, average weight of students of A, B, C and D = 60 kg
? 45a + 50b + 72c + 80d = 60(a + b + c + d)
? 15a + 10b - 12c - 20d = 0
? 15a = 20d
? a : d = 4 : 3
Correct Answer: 55 yr
Explanation:
Total age of Rashmi and Surbhi (5 yr ago) 20 x 2 = 40 yr.
Total age of Rashmi and Surbhi (at present) = 40 + 5 + 5 = 50 yr.
Total age of Rashmi, Surbhi and Meeta (at present) = 30 x 3 = 90 yr.
? Present age of Meeta = 90 - 50 = 40 yr.
? Age of meeta after 15yr. = 40 + 15 = 55 yr.
Correct Answer: 66 kg
Explanation:
Sum of the weight of A, B, C and D = 67 x 4 = 268 kg
and average weight of A, B , C , D and E = 67 - 2 = 65kg
? Sum of the weight of A, B, C, D and E = 65 x 5 = 325 kg
? Weight of E = 325 - 268 = 57 kg
? Weight of F = 57 + 4 = 61 kg
Now, average weight of F, B, C, D and E = 64 kg
? Sum of the weight of F, B, C, D and E = 64 x 5 = 320 Kg
? Sum of the weights of B, C and D = 320 - 57 - 61 = 202 kg
? Weight of A = 268 - 202 = 66 kg
Correct Answer: 6370
Explanation:
? = 6885.009 - 419.999 - 94.989
= 6885 - 420 - 95 ? 6370
Correct Answer: 101100
Explanation:
530 x 201 = 101103 ? 101100
Correct Answer: 0.25
Explanation:
(2/3) x (6/8) x (2/3) x (3/4) = 1/4 = 0.25
Correct Answer: 385
Explanation:
? = 127/8 x 116/5 + 19/5 x 41/8
= 14732/40 + 779/40 = 15511/40 = 387.7 ? 385
Correct Answer: 425
Explanation:
? = 23/5 x 15/26 x 283.75
? 13/5 x 15/16 x 284 = 426 ? 425
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