Let number of students in the sections
A, B, C and D be a, b, c and d respectively.
Then, total weight of students of sections A = 45a
Total weight of students of section B = 50b
Total weight of students of section C = 72c
Total weight of students of section D = 80d
According to the question,
Average weight of students of sections of A and B = 48 kg
? (45a + 50b)/(a + b) = 48
? 45a +50b = 48a + 48b
? 3a = 2b
? 15a = 10b
And average weight of students of sections B and C = 60 kg
? 50b + 72c = 60(b + c)
? 10b = 12c
Now, average weight of students of A, B, C and D = 60 kg
? 45a + 50b + 72c + 80d = 60(a + b + c + d)
? 15a + 10b - 12c - 20d = 0
? 15a = 20d
? a : d = 4 : 3
Let x% of y = y% of A, then
? xy / 100 = yA/100
? A = (xy/100) x (100/y) = x
Let 371/2% of A = 900
? {(75/2) x A} x 100 = 900
? A = (900 x 2 x 100) / 75 = 2400
So, 621/2% of A = (125/2) x (1/100) x 2400 =1500
Let A - 6% of A = AB.
? (94 x A) / 100 = AB
? B = 0.94
Let original price = Rs. 100
? Increase price = Rs. 160
? Decrease on Rs. 160 = Rs. 60
? Decrease on Rs. 100 = (60/160) x 100 % = 371/2%
?(3.6/100) x 40
= ?1.44 = 1.2
Minimum passing marks = 50 + 50 = 100
Let the total marks = x
Then, 50% of x = 100
? x = (100/50) x 100 = 200
Profit or loss percent = ab/100 %
= (20 x 20)/100 %
= -4%
5% of 50% of 500
= (5/100) x (50/100) x 500
= 12.5
Let the required amount of money be N.
Then, N x 25% = 180 x 121/2%
? N = (180 x 12.5)/25
= ? 90
Monthly income of a person = ? 5000
Increment in income = (30/100) x 5000 = 1500
New income = 5000 + 15000 = ? 6500
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.