Let the total number of workers be y.
So sum of salary for all workers = sum of salary of 7 technician + sum of salary for other y -7 workers.
7 x 1000 + 780(y -7) = 850 y
? 7000 + 780y - 5460 = 850y
? 70y = 1540
? y = 22
So total number of workers = 22
Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x18 + 4 x 22 -20
= Rs. 140
? Average earning = 140 / 7
= Rs. 20
Let third number = y
Then, second number = 2y
and first number =4y
? ( y + 2y + 4y) / 3 = 42
? 7y = 42 x 3
? y = 18
so, (largest) - (smallest) = ( 4y - y)
= 3y
=54
Let the present ages of father be 3x and daughter be x .
so the 4 year ago father's age and daughter's age was
( 3x - 4 ) and ( x - 4 )
? ( 3x - 4 / x -4 ) = 4 / 1
? x = 12 year and 3x = 36 year
Required average
= Old average - Sold average
= ( 250 ) - ( 10 ) = 240
Let the number of failed student = Y
? Number of passed student = 80 - Y
sum of marks of all students = sum of marks of passed students + sum of marks of failed students
80 x 40 = (80 - Y) x 60 + 35Y
? 3200 =4800 - 60Y + 35Y
? 25Y = 1600
? Y = 64
? Number of students who failed = 64
Weight increase = 8 x 2 kg = 16 kg
weight of new man= 50 + 16 = 66 kg
Weight of the teacher = Total weight of 40 students and teacher - total weight of 40 students
= 41 x 40.5 - 40 x 40 kg
= 60.5kg
New average = 120% of old average
=120% of 18.5
= (120 x 18.5) / 100
= 22.2
Age of coach = Total weight of 4 players and coach - total weight of 4 players
= 5 x 22.2 - 4 x 18.5
= 37 years
Let the age of youngest child be y.
so from question y + (y + 4) + (y + 8) + (y + 12) = 4 x 12
? 4y + 24= 48
? y = 6 years
Production during these 5 days = Total production in a month - production in first 25 days.
= 30 x 58 - 25 x 60
= 240
? Average for last 5 days = 240 / 5
= 48
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