Required average
= Old average - Sold average
= ( 250 ) - ( 10 ) = 240
Let the number of failed student = Y
? Number of passed student = 80 - Y
sum of marks of all students = sum of marks of passed students + sum of marks of failed students
80 x 40 = (80 - Y) x 60 + 35Y
? 3200 =4800 - 60Y + 35Y
? 25Y = 1600
? Y = 64
? Number of students who failed = 64
Let ages of Dinesh, Mahesh and Rahul be D, M and R, respectively.
Then,
D + M = 2 x 16 = 32 ...(i)
M + R = 2 x 13 = 26 ....(ii)
D + R = 2 x14 = 28 ....(iii)
On adding Eqs. (i), (ii) and (iii), we get
2(D + M + R) =86
? D + M + R = 43 ....(iv)
On subtracting Eqs. (iii) from Eq. (iv), we get
M = 43 - 28
? M = 15 Yr
Let the number of women workers be Y.
Then, 22y + 16 x 8 = 15 (16+y)
? 22y + 128 = 240 + 15y
? 22y - 15y= 240 - 128
? y = 16
? Unmarried women workers = 16 - 10 = 6
Total marks for three examinations = 3x 500 = 1500
Total required marks in three examinations = 60% of 1500
=( 3 x 500 x 60 ) / 100
= 900
Marks secured in first examination = 45 % of 500
=( 500 x 45 ) / 100
=225
Marks secured in third examination = 55 % of 500
=( 500 x 55 ) / 100
=275
Thus, the required marks in third examination
=900 - ( 225 + 275 )
=900 - 500
= 400
Total age of 5 sister = 20 x 5 = 100 yr.
4 yr ago, total sum of ages
= 100 - ( 5 x 4) = 100 - 20 = 80 yr
But at that time (4 yr ago), there were 4 sister in the group.
? Average age at that time(4 yr ago) = 80/4 = 20 yr.
Let the present ages of father be 3x and daughter be x .
so the 4 year ago father's age and daughter's age was
( 3x - 4 ) and ( x - 4 )
? ( 3x - 4 / x -4 ) = 4 / 1
? x = 12 year and 3x = 36 year
Let third number = y
Then, second number = 2y
and first number =4y
? ( y + 2y + 4y) / 3 = 42
? 7y = 42 x 3
? y = 18
so, (largest) - (smallest) = ( 4y - y)
= 3y
=54
Total earning for the week = Sum of earning of first four days + Sum of earning of last four days - Earning of 4th day
= 4 x18 + 4 x 22 -20
= Rs. 140
? Average earning = 140 / 7
= Rs. 20
Let the total number of workers be y.
So sum of salary for all workers = sum of salary of 7 technician + sum of salary for other y -7 workers.
7 x 1000 + 780(y -7) = 850 y
? 7000 + 780y - 5460 = 850y
? 70y = 1540
? y = 22
So total number of workers = 22
Weight increase = 8 x 2 kg = 16 kg
weight of new man= 50 + 16 = 66 kg
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