Total marks for three examinations = 3x 500 = 1500
Total required marks in three examinations = 60% of 1500
=( 3 x 500 x 60 ) / 100
= 900
Marks secured in first examination = 45 % of 500
=( 500 x 45 ) / 100
=225
Marks secured in third examination = 55 % of 500
=( 500 x 55 ) / 100
=275
Thus, the required marks in third examination
=900 - ( 225 + 275 )
=900 - 500
= 400
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.