Total marks for three examinations = 3x 500 = 1500
Total required marks in three examinations = 60% of 1500
=( 3 x 500 x 60 ) / 100
= 900
Marks secured in first examination = 45 % of 500
=( 500 x 45 ) / 100
=225
Marks secured in third examination = 55 % of 500
=( 500 x 55 ) / 100
=275
Thus, the required marks in third examination
=900 - ( 225 + 275 )
=900 - 500
= 400
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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