Given that, number of boys (n1) = 15
Numbers of girls (n2)= 10
Average weight of boys and girls = 38.4 kg
Average of boys = 40 kg
Let average of girls be a2
By formula, average = (na1 + n2 a2) / (n1 + n2)
? 38.4 = (15(40) + 10 x a2)/(15 + 10)
? 38.4 x 25 = 600+ 10a2
? a2= (960 - 600)/10 = 360/10 = 36 kg
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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