Here, n = 10, a = 60, b = 62
Number of runs scored in 11th inning
= n (b - a) + b
= 10 (62 - 60) + 62
= 20 + 62 = 82
Here n1 = 19, a1 = 74, n2 = 38, a1 = 63
Total average weight = (n1a1 + n2 a2) / (n1 + n2)
= [(19) (74) + (38) (63)] / (19 + 38)
= 3800/57 ? 67 kg
According to the fundamental to the fundamental formula
Average(A)= Sum (S) / Number(N)
From the question 60 = S / 13
? S = 60 x 13 = 780
Sum of first seven result = 59 x 7 = 413
Sum of last seven result = 61 x 7 = 427
? 7th result = (Sum of first seven result) + (Sum of last seven results) - (Sum of all the results)
= (413 + 427 - 780 )
= (840 - 780)
= 60
NoteSum of first seven when added to the sum of last seven result, then repetition of 7th result takes place.
Overall height = (n1a1 + n2a2) / (n1 + n2)
n1= 20,
a1 = 5 ft 11 inches = 5 x 12 + 11 = 71 inches
n2= 18,
a2 = 6 ft 2 inches = 6 x 12 + 2 = 74 inches
? Overall height = [(20) (71) + (18) (74)] / (20+18)
= (1420 + 1332) / 38 = 72.42 inches
Let the numbers A, B, C, and D are N , N+1, N + 2 and N + 3, respectively.
According to the question,
[N + (N+1) + (N+2) + (N+3)] / 4 = 49.5
? 4N + 6 = 4 x 49.5
? 4N = 198 - 6 ? N = 192/4
? N = 48
The required product = B x D
= (N + 1) x (N + 3)
= (48 +1) (48 +3 )
= 49 x 51
= 2499
Total age of 30 girls = 30 x 13 = 390 yr
Total age of 18 girls = 18 x 15 = 270 yr.
? Age of remaining 12 girls = 390 - 270 = 120 yr
? Required average = 120/12 = 10 yr
Here n= 34, a = 42 and b = 42.4
Weight of the teacher.
= n(b -a) + b
= 34 ( 42.4 - 42) + 42.4
= 13.6 + 42.4 = 56.0 kg
Here, n = 21, a = 64, b = 65
Weight of teacher = n(b - a) + b
= 21( 65 - 64) + 65
= 21 + 65
= 86 kg
Sum of 14 girls and teacher age = 15 x 15 = 225
Without teacher's age sum of 14 girls age = 14 x 14 = 196
? Teacher's age = 225 -196 = 29 year
Let the number of students in the class = N
According to the question,
(35N + 6 x 33) / (N + 6) = 35 - (1/2)
? 35N + 198 = 34.5 (N + 6)
? 35N +198 = 34.5N + 207
? 0.5N = 207 -198N = 9/0.5 = 18
? N = 18 days
Total age of 5 members = 25 x 5 = 125 yr
Total age of 5 member and the servant
= (25 + 25 x 40/100) x 6
= 35 x 6 = 210 yr
? Age of the servant = 210 - 125 = 85 yr
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