From question
M + T + W + TH = 4 x 38° = 152°
? T + W + TH =152° ? 30° = 122°
Again from question
? T + W + TH + F = 4 x 40° = 160°
? F = 160° ? 122°
= 38°
Thirteenth Result = sum of all 25 results - sum of first 12 results - sum of last 12 results.
= 25 x 18 - 12 x 14 ? 12 x 17
=78
Seventh Result = sum of first 7 results + sum of last 7 results - sum of all 13 results.
? Seventh Result = (7 x 63) + (7 x 70) - (13 x 68 )
=47
New sum of numbers = previous sum - 26 + 36
=10 x 15 - 26 + 36
= 160
? Correct Average = 160 / 10 = 16.
Let total journey be y km.
From question y/35 - y/40= 15/60
? y = ( 35 x 40 )/ ( 4 x 5 ) = 70
? Total Journey = 70 km
Let total journey = y km
Total time taken = time taken during 60% of distance + time taken during 20% of distance + time taken in remaining distance
= [( 60y / 100 ) / 30] + [( 20y / 100 ) / 20] + [( 20y / 100 ) / 10]
= ( y / 50 + y / 100 + y / 50 )hrs
= y/20 hours.
Average speed = total distance traveled / total time taken.
= [y / ( y/20 )] km/hr
=20 km/hr.
Sum of 5 consecutive integers
x + ( x +1 ) + ( x +2 ) + ( x + 3 ) + ( x +4 ) = 5n
? 5x + 10 = 5n
? x = ( n ? 2 ) ......(i)
Average of 7 consecutive integers
= [( 5x + 10 ) + ( x + 5 ) + ( x + 6 )] / 7
= 7x + 21 / 7
= x + 3 .....(ii)
from eq. (i) and (ii)
New average = x + 3 = ( n ? 2 + 3 ) = n + 1
So , the new average increases by 1 .
Let the number of wickets taken before the last match = y
Bowler's overall average = total run scored / total wicket taken by bowler
Then, (12.4y + 26 ) / (y + 5) = 12
? x = 85
Let the original expenditure be Rs. y per day ,
Then, y / 35 - [( y + 42 ) / 42 ] = 1
? 42y - 35 ( y + 42 ) = 35 x 42
? 7y = 35 x 42 + 35 x 42
? y = ( 2 x 35 x 42 ) / 7
= 420
Hence , the original expenditure is Rs . 420
Age of child = sum of age of husband , wife and child - sum of age of husband and wife.
= [(20 x 3) - (23 x 2 + 5 x 2)] years
= 4 years.
Let the age of youngest child be y.
Then y + ( y + 2 ) = ( 24 x 6 ) - ( 24 x 4 + 4 x 10)
= 144 - 136
? 2y + 2 = 8
? y =3 years
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