Average of a,b and c is 11, average of c,d and e is 17 average of e and f is 22 and the average of e and c is 17 . Find out the average of a, b, c, d, e and f.

Sum of the ages of 4 men five years ago
= 48 x 4
=192 yr

And sum of present ages of the four men
= 192 + 5 x 4
= 212 yr

Now ( 212 + Age of the new man ) / 5 = 50
? Age of the new man = 50 x 5 - 212
= 38 yr.

Let the temperature on the last day of the week be x° C

Average of the week = ( 3 x 25 + 3 x 27 + x ) / 7 = 26.5
? 3 x 25 + 3 x 27 + x = 7 x 26.5
? 156+ x = 185.5
? x = 29.5
So, the temprature on the last day of the week is 29.5° C

Total Income of the family per month
= 5 x 1000
= ? 5000

Increased amount per month = 12000/12 = ? 1000

Now, total amount of family income = ? 6000 per month

So, the average income of the family per month after increase = 6000/5
= ? 1200

Monthly sale = yearly sale / 2
= 132000 / 2
= ? 11000

June's sale = monthly sale / 2
= 11000 / 2
= ? 1000

Correct mean = ( sum of total marks - 57 + 75 ) / 30
= ( 30 x 58.5 - 57 + 75 ) / 30
= (1755 + 18 ) / 30
= 59.1

Average cost =( w₁x₁ + w₂x₂ + w₃x₃ ) / (w₁ +w₂ +w₃)

= ( 1200 x 30 +1500 x 25 + 2000 x 32) / ( 1200 + 1500 + 2000 )
= 137500 / 4700
= ? 29.25 per kg

Age of A : age of B : age of C = 3 : 5 : 7
So the average age of 3 boys (3x + 5x + 7x ) /3 = 15
?15x= 15 x 3
? x= 3

sum of odd number upto 100 = 1 + 3 + 5 + 7+....+ 95 + 97 + 99
=(1+99) + (3+97) + (5+95) +.... upto 25 terms
= 100 + 100 + 100 +.... upto 25 terms
= 2500

Average = 2500 /50
= 50

Let total journey = y km
Total time taken = time taken during 60% of distance + time taken during 20% of distance + time taken in remaining distance
= [( 60y / 100 ) / 30] + [( 20y / 100 ) / 20] + [( 20y / 100 ) / 10]
= ( y / 50 + y / 100 + y / 50 )hrs
= y/20 hours.

Average speed = total distance traveled / total time taken.
= [y / ( y/20 )] km/hr
=20 km/hr.

Let total journey be y km.
From question y/35 - y/40= 15/60
? y = ( 35 x 40 )/ ( 4 x 5 ) = 70
? Total Journey = 70 km