a + b + c = 11 x 3 = 33 .....(i)
c + d + e = 17 x 3 = 51 .....(ii)
e + f = 22 x 2 = 44 .....(iii)
e + c = 17 x 2 = 34 .....(iv)
From Eqs. (ii) and (iv), we get
34 + d = 51
? d = 17
Now adding Eqs. (i), (ii), (v), we get
a + b + c + d + e + f = 33 + 44 + 17 = 94
? Average of a, b, c, d, e and f = 94/6 = 152?3
Total population = 300000
Total number of males = 180000
Total Literates = 50% of total population = 150000
Number of literate males = 70% of males = 126000
? Number of literate females = 150000 - 126000 = 24000
Let price = Rs. 100, sale = 100
Then sale value = Rs. (100 x 100) = Rs. 10000
New sale value = Rs. (70 x 120) = Rs. 8400
Decrease% = (1600/10000) x 100 % = 16%
Let the maximum marks be N .
According to the question,
Then, 780 - 728 = 5% of N
? 52 = 5% of N
? N = 5200/5 = 1040
Let his income be Rs. N, then N - 5% of N - 20% of 95% of N = 1919
? N - N/20 - (20 x 95 x N)/(100 x 100) = 1919
? N - N/20 - 19N/100 = 1919
? 100N - 5N - 9N = 191900
? N = 191900 / 76 = 2525
? 721/2% of N = 87
? {(145/2) x N} / 100 = 87
? N = (87 x 2 x 100) / 145 = 120
Let third number be N
Then, first number = 70% of N = 7N/10 and,
Second number = 63% of N = 63N/100
Difference = 7N/10 - 63N/100 = 7N/100
? Required percentage = (7N/100) x (10/7N) x 100 % = 10%
Reduction in consumption = (20/120) x 100% = 50/3%
? Reduction in consumption /Original consumption = (50/3) / 100 = 1/6 = 1 : 6
Let tax = Rs. 100 and Consumption = 100 units
Original expenditure = Rs. (100 x 100) = 10000
New expenditure = Rs. (120 x 80) = Rs. 9600
? Decreased in expenditure = (400 x 100)/1000 % = 4%
Alcohol in 15 litres =(20 x 15)/100 litres = 3 litres
Now, alcohol in 18 litres = 3 litres
? strength of alcohal =(3/18) x 100 % = 162/3%
Value of machine 2 years later = Rs. [ 4000 x {(1 - 10)/10)}2]
= Rs. (4000 x 9/10 x 9/10)
= Rs. 3240
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