Sum of the ages of 4 men five years ago
= 48 x 4
=192 yr
And sum of present ages of the four men
= 192 + 5 x 4
= 212 yr
Now ( 212 + Age of the new man ) / 5 = 50
? Age of the new man = 50 x 5 - 212
= 38 yr.
Let the temperature on the last day of the week be x° C
Average of the week = ( 3 x 25 + 3 x 27 + x ) / 7 = 26.5
? 3 x 25 + 3 x 27 + x = 7 x 26.5
? 156+ x = 185.5
? x = 29.5
So, the temprature on the last day of the week is 29.5° C
Total Income of the family per month
= 5 x 1000
= ? 5000
Increased amount per month = 12000/12 = ? 1000
Now, total amount of family income = ? 6000 per month
So, the average income of the family per month after increase = 6000/5
= ? 1200
Monthly sale = yearly sale / 2
= 132000 / 2
= ? 11000
June's sale = monthly sale / 2
= 11000 / 2
= ? 1000
Correct mean = ( sum of total marks - 57 + 75 ) / 30
= ( 30 x 58.5 - 57 + 75 ) / 30
= (1755 + 18 ) / 30
= 59.1
Total required marks in the three examinations = (3 x 600 x 70)/100 =1260
Marks secured in first examination = 55% of 600 = ( 600 x 55)/100 =330
Marks secured in second examination = 60% of 600 = ( 600 x 60)/100 =360
Thus, the required marks in third examination = 1260 - (330 + 360)
= 1260 - 690
= 570
a + b + c = 11 x 3 = 33 .....(i)
c + d + e = 17 x 3 = 51 .....(ii)
e + f = 22 x 2 = 44 .....(iii)
e + c = 17 x 2 = 34 .....(iv)
From Eqs. (ii) and (iv), we get
34 + d = 51
? d = 17
Now adding Eqs. (i), (ii), (v), we get
a + b + c + d + e + f = 33 + 44 + 17 = 94
? Average of a, b, c, d, e and f = 94/6 = 152?3
Average cost =( w1x1 + w2x2 + w3x3 ) / (w1 +w2 +w3)
= ( 1200 x 30 +1500 x 25 + 2000 x 32) / ( 1200 + 1500 + 2000 )
= 137500 / 4700
= ? 29.25 per kg
Age of A : age of B : age of C = 3 : 5 : 7
So the average age of 3 boys (3x + 5x + 7x ) /3 = 15
?15x= 15 x 3
? x= 3
sum of odd number upto 100 = 1 + 3 + 5 + 7+....+ 95 + 97 + 99
=(1+99) + (3+97) + (5+95) +.... upto 25 terms
= 100 + 100 + 100 +.... upto 25 terms
= 2500
Average = 2500 /50
= 50
Let total journey = y km
Total time taken = time taken during 60% of distance + time taken during 20% of distance + time taken in remaining distance
= [( 60y / 100 ) / 30] + [( 20y / 100 ) / 20] + [( 20y / 100 ) / 10]
= ( y / 50 + y / 100 + y / 50 )hrs
= y/20 hours.
Average speed = total distance traveled / total time taken.
= [y / ( y/20 )] km/hr
=20 km/hr.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.