Total required marks in the three examinations = (3 x 600 x 70)/100 =1260
Marks secured in first examination = 55% of 600 = ( 600 x 55)/100 =330
Marks secured in second examination = 60% of 600 = ( 600 x 60)/100 =360
Thus, the required marks in third examination = 1260 - (330 + 360)
= 1260 - 690
= 570
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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