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- Question
- The Average of six observation is 12. The average decreases by 1 when a new observation is included. What is the seventh observation?
Options- A. 1
- B. 3
- C. 5
- D. 6
- Correct Answer
- 5
ExplanationTotal of 6 observation = 6 x 12 = 72
Total of 7 observation (including the 7th) = 7 x (12 - 1) = 77
? 7th observation = 77 - 72 = 5 - 1. The average of nine numbers is 50. The average of the first five numbers is 54 and that of the last three numbers is 52. Then the sixth number is
Options- A. 34
- B. 24
- C. 44
- D. 30 Discuss
- 2. Find the average of all prime numbers between 60 and 90.
Options- A. 72
- B. 74.7
- C. 74
- D. 73.6 Discuss
- 3. Find the average of the following set of scores. 124, 856, 331, 227, 963, 338, 259, and 662
Options- A. 570
- B. 660
- C. 141
- D. 350 Discuss
- 4. Find the average of the following set of scores 253, 124, 255, 534, 836, 375, 101, 443, 760
Options- A. 427
- B. 413
- C. 141
- D. 490 Discuss
- 5. The sum of seven numbers is 235. The average of the first three is 23 and that of the last three is 42. The fourth number is?
Options- A. 40
- B. 126
- C. 69
- D. 195 Discuss
- 6. Average to ten number is 7 . If every number is multiplied by 12, What will be the average of new numbers?
Options- A. 7
- B. 9
- C. 82
- D. 84 Discuss
- 7. The average weight of 60 students in a class was calculated to be 40 kg. Later it was found out that the weight of one of the students was calculated as 36 kg, whereas his actual weight was 33 kg. What is the actual average weight of the students in the class?
Options- A. 39.90 kg
- B. 39.95 kg
- C. 39 kg
- D. 38 kg Discuss
- 8. A batsman has a certain average of runs for 14th innings. He scores 72 runs in the 15th innings, thus his average increased by 2. Find the average after 15th innings.
Options- A. 44
- B. 46
- C. 42
- D. 48 Discuss
- 9. The Average of 5 observation is 15. If three new observation 16.5, 18 and 14.5 be added. Then find the new average.
Options- A. 14.8
- B. 15.5
- C. 16.2
- D. 15.6 Discuss
- 10. The average of x 1, x 2 and x 3 is 14. Twice the sum of x 2 and x 3 is 30. What is the value of x 1?
Options- A. 20
- B. 27
- C. 16
- D. 2 Discuss
Average problems
Search Results
Correct Answer: 24
Explanation:
Required number = (Sum of all numbers) - [(Sum of first 5 numbers) + (Sum of last 3 numbers)
= 50 x 9 - ( 54 x 5 + 3 x 52)
= 450 - (270 + 156) = 450 - 426 ? 24
Correct Answer: 74.7
Explanation:
Average of all prime numbers between 60 and 90
= (61 + 67 + 71 + 73 + 79 + 83 + 89)/7
= 523/7 = 74.7
Correct Answer:
Explanation:
Required average = ( Sum of scores) / (No of scores)
= (124 + 856 + 331 + 227 + 963 + 338 + 259 + 662)/8
= 3760/8 = 470
Correct Answer:
Explanation:
Required average = (Sum of all scores) / (Number of scores)
= (235 + 124 + 255 + 534 + 836 + 375 + 101 + 433 + 760)/9
= 3681/9= 409
Correct Answer: 40
Explanation:
Sum of 7 numbers = sum of first 3 numbers + N4 + sum of last 3 numbers.
(23 x 3) + N4 + (42 x 3) = 235
? N4 = 40
? 4th number = 40
Correct Answer: 84
Explanation:
Here initial average = 7
As we know that, if all the numbers are multiple by a certain number, then their average must be a multiple of that number.
? New average = 7 x 12 = 84
Correct Answer: 39.95 kg
Explanation:
Total correct weight = (40 x 60) - 36 + 33 = 2400 - 3 = 2397 kg
? Required average weight = 2397/60 = 39.95 kg
Correct Answer: 44
Explanation:
Let the average of 14th innings = x
? Average of 15th innings = x+2
Then, 14x+72 = 15(x+2)
? 14x+72 = 15x +30
? x = 42
? Average for 15th innings = x+2 = 42 + 2 = 44
Correct Answer: 15.5
Explanation:
Total of 5 observations = 5 x 15 = 75
New sum = 75 + 16.5 + 18 + 14.5 = 124
New Average = 124 ? 8 = 15.5
Correct Answer: 27
Explanation:
x1 + x2 + x3 = 3 x 14 = 42 ....(i)
and (x1 + x2) x 2 = 30
? x1 + x2 =15 ....(ii)
From Eqs. (i) and (ii), we get
x1 + 15 = 42
? x1 = 42 - 15 = 27
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